This is the concept of application of quadratic expressions. Given that the height of the ball is modeled by the equation;
h=-7.3t^2+8.25t+2.1+5
The time taken for the ball to hit the ground will be given as falls;
-7.3t^2+8.25t+7.1=0
to solve for t we use the quadratic formula;
t=[-b+/-sqrt(b^2-4ac)]/(2a)
a=-7.3, b=8.25, c=2.1
t=[-8.25+/-sqrt[8.25^2+4*7.3*7.1]/(-2*7.3)
t= -0.572
or
t=1.702
since there is not negative time we take the time taken for the ball to hit the ground will be: t=1.702 sec
Step-by-step explanation:
x^2+x-6006=0
x^2+78x-77x-6006=0
x(x+78)-77(x+78)=0
(x-77)(x+78)=0
=>x=77 or x=78
Answer:
42 minutes
Step-by-step explanation:
70% x T = 98
7T/10 = 98
7T = 980
T = 140 mins
140 - 98
= 42 minutes
Answer: Y = 1/4x - 2
Slope intercept form is y = mx + b
M is slope, and b is y intercept
Solving slope:
change in y over change in x is slope
The change in y from (0,-2) and (4,-1) is up one over four.
This can be represented as 1/4
Solving y-intercept:
Y-intercept is when x = 0 or when the line touches the y axis
As you can see on the graph, the y intercept is (0,-2) or -2
Final:
Y = 1/4x - 2
