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3 years ago

Solve this equation for a. A ÷ 2 = 4 a. 8 B. 2 C. 6 D. 4

Mathematics

2 answers:

Contact [7]3 years ago

8 0

A=8.8/2=4 8 is the answer

Sergio [31]3 years ago

3 0

A ÷ 2 = 4

Multiply both sides by 2.

a ÷ 2 × 2= 4 × 2

a = 4 × 2

a = 8

Your final answer is A. 8<span>.</span>

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The answer is 1.5ft.

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3 years ago

Is it possible to build a triangle with inside angles of 90 degrees , 50 degrees, and 60 degrees?

N76 [4]

Answer:

Step-by-step explanation:

Given: Angles of a triangle are equal to 90 degrees , 50 degrees, and 60 degrees

To check : if it possible to build a triangle with given angles

Solution:

According to angle sum property of a triangle, sum of angles of a triangle is equal to $180^{\circ}$

Here,

sum of given angles = $90^{\circ}+50^{\circ}+60^{\circ}=200^{\circ}\neq 180^{\circ}$

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2 years ago

The volume of a cylinder is 375 pi m^3. if r= 5 m, find its height.

pishuonlain [190]

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Step-by-step explanation:

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3 years ago

Can you find the slope for me, please?

shusha [124]

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3 0

2 years ago

Read 2 more answers

HELP ME PLEASE

solmaris [256]

Answer:

The initial mass of the sample was 16 mg.

The mass after 5 weeks will be about 0.0372 mg.

Step-by-step explanation:

We can write an exponential function to model the situation.

Let the initial amount be A. The standard exponential function is given by:

$P(t)=A(r)^t$

Where r is the rate of growth/decay.

Since the half-life of Palladium-100 is four days, r = 1/2. We will also substitute t/4 for t to to represent one cycle every four days. Therefore:

$\displaystyle P(t)=A\Big(\frac{1}{2}\Big)^{t/4}$

After 12 days, a sample of Palladium-100 has been reduced to a mass of two milligrams.

Therefore, when x = 12, P(x) = 2. By substitution:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^{12/4}$

Solve for A. Simplify:

$\displaystyle 2=A\Big(\frac{1}{2}\Big)^3$

Simplify:

$\displaystyle 2=A\Big(\frac{1}{8}\Big)$

Thus, the initial mass of the sample was:

$A=16\text{ mg}$

5 weeks is equivalent to 35 days. Therefore, we can find P(35):

$\displaystyle P(35)=16\Big(\frac{1}{2}\Big)^{35/4}\approx0.0372\text{ mg}$

About 0.0372 mg will be left of the original 16 mg sample after 5 weeks.

5 0

3 years ago