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3 years ago

10

Dakota is going to buy a rug to cover her entire kitchen floor. The width of her kitchen is 4.5 meters. The length is 8.5 meters

. What is the area of the rug that Dakota needs to buy?

1 answer:

Rus_ich [418]3 years ago

7 0

Answer:

38.25

Step-by-step explanation:

It is 4.5 times 8.5 which is 38.25

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What is the area of the trapezoid with height 10 units?

aleksley [76]

If by "long leg lengths" you mean the hypotenuse then the area is 116 sq. units. If you mean the bases of the triangles then the area is 170 sq. units.

If the length of 12 is the hypotenuse, we first must find the base of the triangles using the Pythagorean theorem:

10² + b² = 12²

100 + b² = 144

b² = 44

b = √44 = 6.6

This means we have two triangles and a rectangle. The area of the rectangle is 5(10) = 50 sq. units. The area of each triangle is 1/2(6.6)(10) = 33. Adding all 3 together we have:

50+33+33 = 116 sq. units.

If the 12 is the base, then we have the rectangle with the area of 5(10) = 50 and two triangles each with an area of 1/2(12)(10) = 60:

50+60+60 = 170 sq. units.

3 0

3 years ago

Help please, 25 points.

Roman55 [17]

Consistent and dependent

The lines are the same

4 0

3 years ago

A^2+5A+4 (A=-5). Evaluate the expression

Naddik [55]

Answer:

4

Step-by-step explanation:

First, rewrite the equation with -5 substituted for A: (-5)^2 +5(-5) +4
Next, simplify that equation: 25 -25 +4
Simplify this further: 4

When A=-5, the solution is 4.

8 0

2 years ago

Describe the steps you would use to factor 2x3 + 5x2 – 8x – 20 completely. Then state the factored form.

WARRIOR [948]

The polynomial $2x^3 + 5x^2-8x-20$ may have solutions which are the divisors of -20, therefore -20 has the following divisors: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .
If x=1, then $2\cdot1^3 + 5\cdot1^2-8\cdot1-20=-20\neq 0$ ,
if x=-1, then $2\cdot(-1)^3 + 5\cdot(-1)^2-8\cdot(-1)-20=-9\neq 0$ ,
if x=2, then $2\cdot2^3 + 5\cdot2^2-8\cdot2-20=0$ , then x=2 is a solution and you have the first factor (x-2).
If x=-2, then $2\cdot(-2)^3 + 5\cdot(-2)^2-8\cdot(-2)-20=0$ , then x=-2 is a solution, so you have the second factor (x+2).
Since x-2 and x+2 are two factors of $2x^3 + 5x^2-8x-20$ , then the polynomial $x^2-4$ is a divisor of $2x^3 + 5x^2-8x-20$ and dividing the polynomial $2x^3 + 5x^2-8x-20$ by $x^2-4$ you obtain
$2x^3 + 5x^2-8x-20=(x-2)(x+2)(2x+5)$ .

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lys-0071 [83]

Answer:The answer Is D

Step-by-step explanation:

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