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Tamiku [17]
3 years ago
13

Determine the number solutions for system x-2y=1 and -4x+8y=-4

Mathematics
1 answer:
stellarik [79]3 years ago
6 0

Answer:

Hence, the system of equation does not have solution.

Step-by-step explanation:

You have the following 2x2 system:

x-2y=1\ \ \ \ (1)\\\\-4x+8y=-4\ \ \ \ (2)

You can obtain the solution to the system by using substitution method.

You solve the first equation for x:

x=1+2y       (3)

Next, you replace (3) in the equation (2), and you solve for y:

-4(1+2y)+8y=-4\\\\-4-8y+8y=-4\\\\0=0

The last result is the trivial solution. This means that the equation (2) is a multiple scale of the first equation. In fact, if you multiply equation (1) by -4, you obtain the equation (2).

Hence, the system of equations does not have solution.

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Answer:

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<u><em>First, solve the inequality (Isolate the y-variable & put it in function format):</em></u>

<u><em /></u>6x - 2y > 8\\-2y > 8 - 6x\\(-1)(-2y) > (-1)(8-6x)\\2y < 6x-8\\y < \frac{6x-8}{2} \\y < 3x - 4

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  • It should be linear.
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