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Tamiku [17]
4 years ago
13

Determine the number solutions for system x-2y=1 and -4x+8y=-4

Mathematics
1 answer:
stellarik [79]4 years ago
6 0

Answer:

Hence, the system of equation does not have solution.

Step-by-step explanation:

You have the following 2x2 system:

x-2y=1\ \ \ \ (1)\\\\-4x+8y=-4\ \ \ \ (2)

You can obtain the solution to the system by using substitution method.

You solve the first equation for x:

x=1+2y       (3)

Next, you replace (3) in the equation (2), and you solve for y:

-4(1+2y)+8y=-4\\\\-4-8y+8y=-4\\\\0=0

The last result is the trivial solution. This means that the equation (2) is a multiple scale of the first equation. In fact, if you multiply equation (1) by -4, you obtain the equation (2).

Hence, the system of equations does not have solution.

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Answer:

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Step-by-step explanation:

Let's start like by solving the order of operations, and then add our Y's:

7y + 7 + −8y + 56

Adding:

+63 - y

Simplifying:

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3 years ago
Find the fifth term of a geometric sequence for which a3= 20 and r= 2.
Dahasolnce [82]

Answer:

The fith number is 80.

Step-by-step explanation:

A geometric sequence is a group of numbers that are related to it's neighbours by a product of a constant ratio. In order to calculate a certain number in such sequences we can use the formula:

an = a1*q^(n-1)

Where "n" is the position of the number we wish to know and q is the ratio. To use the formula we need to know the first number and we were given the third, so we first need to find that. We have:

a3 = a1*q^(3 - 1)

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