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2 years ago

Simplify 7y+7-8(y-7)

Mathematics

2 answers:

Salsk061 [2.6K]2 years ago

8 0

Answer:

-y + 63

Step-by-step explanation:

Let's start like by solving the order of operations, and then add our Y's:

7y + 7 + −8y + 56

Adding:

+63 - y

Simplifying:

-y + 63

Thus, our answer is -y + 63

Alex787 [66]2 years ago

5 0

Answer:

-y+63

Step-by-step explanation:

You need to distribute the -8 by multiplying it to y and -7 therefore making 7y+7-y+56. Then you subtract 7y by 8y and then add 7 with 56

As a result, you then get -y + 63

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Answer:

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Step-by-step explanation:

So,here;

a.9.9.3=35 is given

or,243=35 (which is false)

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or,21=21 (which is true)

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2 years ago

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*PLS HELP* I need help on this and please provide an explanation

expeople1 [14]

Answer:

Step-by-step explanation:

Value of x

<h3>Given:-</h3>

46° and (5x - 1)° are complementary angles

<h3>Solution:-</h3>

As we know,

Complementary angles:

The angles whose sum results to 90° are known as the complementary angles.

So,

46° + (5x - 1)° = 90°

[Since complementary angles]

=> 46 + 5x - 1 = 90

[On Simplification]

=> 45 + 5x = 90

[On subtracting both sides with 45]

=> 45 + 5x - 45 = 90 - 45

[On Simplification]

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[On dividing both sides with 5]

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[On Simplification]

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1 year ago

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A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12. Suppose that we take a random

Zielflug [23.3K]

Answer: The 95% confidence interval for the mean of x is (94.08, 101.92) .

Step-by-step explanation:

We are given that ,

A random variable x has a Normal distribution with an unknown mean and a standard deviation of 12.

i.e. $\sigma= 12$

Also, it is given that , Sample mean $\overline{x}=98$ having sample size : n= 36

For 95% confidence ,

Significance level : $\alpha=1-0.95=0.05$

By using the z-value table , the two-tailed critical value for 95% Confidence interval :

$z_{\alpha/2}=z_{0.025}=1.96$

We know that the confidence interval for unknown population mean $(\mu)$ is given by :-

$\overline{x}\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = Sample mean

$\sigma$ = Population standard deviation

$z_{\alpha/2}$ = Critical z-value.

Substitute all the given values, then the required confidence interval will be :

$98\pm (1.96)\dfrac{12}{\sqrt{36}}$

$=98\pm (1.96)\dfrac{12}{6}$

$=98\pm (1.96)(2)$

$=98\pm 3.92=(98-3.92,\ 98+3.92)\\\\=( 94.08,\ 101.92)$

Therefore, the 95% confidence interval for the mean of x is (94.08, 101.92) .

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