Joe has some pocket money.He spends 50% of it.He then had another £1.50.He has 75p left.How much pocket money did he have

Roland bought a dresser for k dollars. After restoring it, he sold it for 3.1k dollars. Which is another way to describe the cha

xxMikexx [17]

Answer: 210 percent increase

Step-by-step explanation: So w know the starting value is k so we can replace it with 1 dollar

now we know he bought the dresser for 1 dollar and sold it for 3.10 dollars

First we have to subtract the starting value 3.1 - the original value

3.1 - 1 = 2.1

then we have to divide that number by the starting value

2.1 divided by 1 = 2.1

Lastly multiply times 100 to get the percent increase

2.1 x 100 = 210 % increase

hope this helps mark me brainliest if it helped

6 0

4 years ago

Pleas answer number 1 ( URGENT )

vesna_86 [32]

Do you know how to add fractions? let me know if u dont

6 0

4 years ago

A park is in the shape of a rectangle. The park authorities are planning to build a 2-meter-wide jogging path in the park (shown

Burka [1]

First, we need to find the area of the two rectangles in this picture. We know that area = l*w.

So for the larger rectangle, we know the l = 100 m, and the w = 60 m. Let us find the area:

$A=100*60=6000 m^{2}$

So the larger rectangle area is 6000 m.

The smaller rectangle has dimensions that are 2 m less on every side. So we can recalculate these dimensions as l = 96 m and w = 56 m.

Let's find the area of the smaller rectangle:

$A=96*56=5,376 m^{2}$

So we know that the area of the smaller rectangle is 5,376 m.

The area of the jogging path is going to be the difference between these two rectangles. Let us solve:

$6,000-5,376=624 m^{2}$

So now we know that the area of the jogging path is $624 m^{2}$ .

5 0

4 years ago

Researchers recorded that a certain bacteria population declined from 200,000 to 900 in 18 hours. At this rate of decay,

salantis [7]

Answer:

9,942 bacteria were there at 10 hours.

Step-by-step explanation:

Equation for population decay:

The equation for population decay, after t hours, is given by:

$P(t) = P(0)(1-r)^t$

In which P(0) is the initial population and r is the decay rate, as a decimal.

Researchers recorded that a certain bacteria population declined from 200,000 to 900 in 18 hours.

This means that $P(0) = 200000$ and that when $t = 18, P(t) = 900$ . So we use this to find r.

$P(t) = P(0)(1-r)^t$

$900 = 200000(1-r)^{18}$

$(1-r)^{18} = \frac{900}{200000}$

$\sqrt[18]{(1-r)^{18}} = \sqrt[18]{\frac{900}{200000}}$

$1 - r = (\frac{900}{200000})^{\frac{1}{18}}$

$1 - r = 0.7407$

So

$P(t) = P(0)(1-r)^t$

$P(t) = 200000(0.7407)^t$

At this rate of decay, how many bacteria was there at 10 hours?

This is P(10). So

$P(10) = 200000(0.7407)^{10} = 9941.5$

Rounding to the nearest whole number:

9,942 bacteria were there at 10 hours.

5 0

3 years ago

The perimeter of a rectangular field is 360yd. The length is 20yd longer than the width. Find the dimensions

Tju [1.3M]

If P=360, then 360yd / 4 sides = 90yds each side. Now that it is a rectangle, the Length should be more than the width, so if the length is 20yds more than the width, do 90 - 20 two times, Width= [ (90yds - 20yds)*2 ]

To sum things up, Length = 110; Width = 70. | 110*2 = 220, 70 * 2 = 140, 220+140 = 360.

5 0

3 years ago

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