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3 years ago

Evaluate 3/2y-3+5\3 z when y =6 and z =3.

Mathematics

1 answer:

agasfer [191]3 years ago

6 0

Answer:

49/4 or 12.25

Step-by-step explanation:

+ We replace y= 6 and z= 3 into this expression: 3/2y-3+5\3 z

+ We find that: $3/2y-3+5\3 z= \frac{3}{2*6} -3+5*3= \frac{1}{4} -3+15 = \frac{1}{4} +12=\frac{49}{4} = 12.25$

The answer is 49/4 or 12.25

Have a good day.

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Reject the null hypothesis

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Step-by-step explanation:

From the question we are told that

The sample size is n = 16

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The number that of students that picked out the teachers dog is k = 14

Generally the sample proportion is mathematically represented as

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The null hypothesis is $H_o : p > 0.5$

Generally the test statistics is mathematically represented as

$z = \frac{\^ p - p }{\sqrt{ \frac{p(1- p )}{n} } }$

$z = \frac{0.875 - 0.50 }{\sqrt{ \frac{0.50 (1- 0.50 )}{16} } }$

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Generally the p-value is mathematically represented as

$p-value = P(Z > 3)$

From the z table the probability of Z>3 is mathematically represented as

$P(Z > 3) = 0.0013499$

$p-value = 0.0013499$

Let assume the level of significance is $\alpha = 0. 05$

Generally from the value obtained we see that $p-value < \alpha$ Hence

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Reject the null hypothesis

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