Question

Consider the reaction.

Answer 1

Answer:

$\large\boxed{\large\boxed{2.0\times 10^{-50}M^-1}}}$

Explanation:

The reaction is:

        $3O_2(g)\rightleftharpoons 2O_3(g)$

The equlibrium constant equation is:

       $K_c=\dfrac{[O_3g)]^2}{[O_2(g)]^3}$

Substitute:

      $K_c=\dfrac{(2.86\times 10^{-28}M)^2}{(1.6\times 10^{-2}M)^3}=2.0\times 10^{-50}M^{-1}$

Answer 2

Answer:

A.) 2.0 x 10*50