Answer:
<h2><em>
vol= 10366.3175in²</em></h2>
<em></em>
Step-by-step explanation:
So this is a cylinder
<h2>formula:
π r²h</h2>
R= 8.75in
h=43.12in
So it will be = 3.14x8.75²x43.12
=> 3.14x76.5625x43.12
3.14x 3301.375
<h2><em>
10366.3175in²</em></h2>
<em></em>
<em>i think it is correct </em>
<em>.</em>
<em>stay safe</em>
<em>.</em>
<em>have a nice TIME</em>
1,038/12= 86.5833333 86x12=1,032
1,039-1,032=7 left over So you’ll need 87 boxes
Would use the algorithm for solving square root.
For square root, √n
x₁ = 0.5(x₀ + n/x₀)
(This formula is known and for square root, and can be derived using Newton-Raphson's approximation equation)
Where x₀ is the initial guess. x₁ becomes the new guess.
For √100.6 let our initial guess be 10, x₀ = 10, n = 100.6
Our approximation shall be to 3 decimal places. Once we get the same answer twice we stop the algorithm.
x₀ = 10, x₁ = 0.5(x₀ + n/x₀), x₁ = 0.5(10 + 100.6/10) = 10.030, x₁ = 10.030
x₂ = 0.5(x₁ + n/x₁), x = 0.5(10.030 + 100.6/10.030) ≈10.015, x₂ ≈ 10.030 (to 3 decimal places)
Since x₂≈ x₁, the algorithm stops.
So the √100.6 is ≈ 10.030 to 3 decimal places.
I hope this helps.
Answer:
2x ^7/4
Step-by-step explanation:
Sorry, no explanation.
