According to <em>graphical</em> and <em>analytical</em> methods, the value of the <em>input</em> variable associated with point of intersection between f(x) and g(x) is 1.5. (Correct choice: C)
<h3>How to determine the point of interception between two linear functions</h3>
<em>Linear</em> functions are polynomials with a grade of 1 and described by the following form:
y = m · x + b (1)
Where:
- x - Independent variable
- m - Slope
- y - Dependent variable
- b - Intercept
Please notice that <em>horizontal</em> lines have a slope of 0.
There are two forms to estimate the coordinates of the point of intersection of the two functions: (i) <em>graphical</em>, (ii) <em>analytical</em>. According to the first method, the value of the <em>input</em> variable is approximately 1.5.
And according to the second method, we have the functions f(x) = 1 and g(x) = (4/3) · x - 1. Then, we must solve the following formula to determine the input variable of the point of interception:
1 = (4/3) · x - 1
(1/3) · x = 1/2
x = 3/2
x = 1.5
The value of the <em>input</em> variable is approximately 1.5.
According to <em>graphical</em> and <em>analytical</em> methods, the value of the <em>input</em> variable associated with point of intersection between f(x) and g(x) is 1.5. (Correct choice: C)
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The answer is 488.
22*17=374
12*19=228
228/2=114
374+114=488
Answer:
![2a^3b^2\sqrt[3]{3a}](https://tex.z-dn.net/?f=2a%5E3b%5E2%5Csqrt%5B3%5D%7B3a%7D)
Step-by-step explanation:
Use the following rules for exponents:
![a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x](https://tex.z-dn.net/?f=a%5Em%2Aa%5En%3Da%5E%7Bm%2Bn%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bx%5E3%7D%3Dx)
Simplify 24. Find two factors of 24, one of which should be a perfect cube:

Insert:
![\sqrt[3]{2^3*3a^{10}b^6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E3%2A3a%5E%7B10%7Db%5E6%7D)
Now split the exponents. Split 10 into as many 3's as possible:

Insert as exponents:
![\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E3%2A3%2Aa%5E3%2Aa%5E3%2Aa%5E3%2Aa%5E1%2Ab%5E6%7D)
Split 6 into as many 3's as possible:

Insert as exponents:
![\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2%5E3%2A3%2Aa%5E3%2Aa%5E3%2Aa%5E3%2Aa%5E1%2Ab%5E3%2Ab%5E3%7D)
Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):
![2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}](https://tex.z-dn.net/?f=2%5Csqrt%5B3%5D%7B3%2Aa%5E3%2Aa%5E3%2Aa%5E3%2Aa%5E1%2Ab%5E3%2Ab%5E3%7D%5C%5C%5C%5C%5C%5C2%2Aa%2Aa%2Aa%5Csqrt%5B3%5D%7B3%2Aa%5E1%2Ab%5E3%2Ab%5E3%7D%5C%5C%5C%5C%5C%5C2%2Aa%2Aa%2Aa%2Ab%2Ab%5Csqrt%5B3%5D%7B3%2Aa%5E1%7D)
Simplify:
![2a^3b^2\sqrt[3]{3a}](https://tex.z-dn.net/?f=2a%5E3b%5E2%5Csqrt%5B3%5D%7B3a%7D)
:Done
Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients. The polynomial whose factors are (a²-6) and (a²+4) is a⁴ - 2a² - 24.
<h3>What is a polynomial?</h3>
Polynomials are mathematical expressions involving variables raised with non-negative integers and coefficients(constants who are in multiplication with those variables) and constants with only operations of addition, subtraction, multiplication and non-negative exponentiation of variables involved.
Example: x²+3x+5 is a polynomial.
The polynomial whose factors are (a²-6) and (a²+4) is,
P(x) = (a²-6)(a²+4)
= a⁴ + 4a² - 6a² - 24
= a⁴ - 2a² - 24
Hence, The polynomial whose factors are (a²-6) and (a²+4) is a⁴ - 2a² - 24.
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Answer:
5 1/3 flour 3 1/5 sugar
Step-by-step explanation: