Answer:
P = 10/171
P = 0.058
The probability that both fish selected are Catfish is 0.0058
Step-by-step explanation:
Given:
The tank contains;
Algae eaters = 8
Catfish = 5
Tilapia fish = 6
Total number of fish = 8+5+6= 19
To determine the probability that both fish selected are Catfish P;
P = 5/19 × 4/18
( The number of the total number of fishes, and Catfish reduce by one after each selection because it is selected without replacement)
P = 10/171
P = 0.058
Answer:
1.D) Procedure results in a binomial distribution.
2. B) Procedure results in a binomial distribution.
Step-by-step explanation:
The binomial distributions has following properties.
- There is always one of the two outcomes success or failure possible.
- The probability of p remains constant for all trials.
- The successive trials are all independent.
- The experiment is repeated for a fixed number of times.
If the experiment has the above properties it has binomial probability distribution.
In the given question both experiments have the above mentioned properties.
Both procedure result in binomial distribution.
Answer:
65%
Step-by-step explanation:
Answer:
=2xy^3x(xy-3)
Step-by-step explanation:
2x^2y4-6xy^3
=2xy^3x(xy-3)
=2xy^3x(xy-3)
