1. Determine whether the given procedure results in a binomial distribution. If not, state the reason why.

Mathematics

1 answer:

Anna11 [10]3 years ago

3 0

Answer:

1.D) Procedure results in a binomial distribution.

2. B) Procedure results in a binomial distribution.

Step-by-step explanation:

The binomial distributions has following properties.

There is always one of the two outcomes success or failure possible.

The probability of p remains constant for all trials.

The successive trials are all independent.

The experiment is repeated for a fixed number of times.

If the experiment has the above properties it has binomial probability distribution.

In the given question both experiments have the above mentioned properties.

Both procedure result in binomial distribution.

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bixtya [17]

He paid ...

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3 years ago

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tatyana61 [14]

Answer:

3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

$\dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}$

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

$\dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}$