Question

Dentify the height for the function: f(t)=2csc(4t-pi/5)+1

Answer 1

Answer with explanation:

 The given function is

      $f(t)=2csc(4t-\frac{\pi}{5})+1$

The values that  Cosecant function ican take is, 0,1, 2,...

So,Height that function can reach is

       $1\rightarrow 2 \times \frac{1}{2}+1\\\\=1+1\\\\=2\\\\2 \rightarrow 2 \times 1+1\\\\=2+1\\\\=3\\\\3 \rightarrow 2 \times 0+1\\\\=0+1\\\\=1$

So,→ Maximum Height from X axis from where the function begin or vertex of the function =3

→Minimum Height from X axis from where the function begin or vertex of the function =1

→And if you will look at the overall height of Function , the y value can reach upto Infinity.      

Option C: 3

Answer 2

The answer is
2csc(4t-0.628)+1