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3 years ago

(Y^2-y+5)/(y+1) Can someone please help me

1 answer:

8 0

Y - 2 + $\frac{7}{y + 1}$

Your teacher may also just want the answer y - 2 with a 7 remainder

Either way, you set it up like long division and solve as such.

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How many times larger is a 10 pound dog than a hamster weighing five eighth pounds

jok3333 [9.3K]

Answer:

about 16 times bigger

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The market and Stock J have the following probability distributions:

denis-greek [22]

Answer:

1) $E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

2) $E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

3) $E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

4) $E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

Step-by-step explanation:

For this case we have the following distributions given:

Probability M J

0.3 14% 22%

0.4 10% 4%

0.3 19% 12%

Part 1

The expected value is given by this formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(M) = 14*0.3 + 10*0.4 + 19*0.3 = 13.9 \%$

Part 2

$E(J)= 22*0.3 + 4*0.4 + 12*0.3 = 11.8 \%$

Part 3

We can calculate the second moment first with the following formula:

$E(M^2) = 14^2*0.3 + 10^2*0.4 + 19^2*0.3 = 207.1$

And the variance would be given by:

$Var (M)= E(M^2) -[E(M)]^2 = 207.1 -(13.9^2)= 13.89$

And the deviation would be:

$Sd(M) = \sqrt{13.89}= 3.73$

Part 4

We can calculate the second moment first with the following formula:

$E(J^2) = 22^2*0.3 + 4^2*0.4 + 12^2*0.3 =194.8$

And the variance would be given by:

$Var (J)= E(J^2) -[E(J)]^2 = 194.8 -(11.8^2)= 55.56$

And the deviation would be:

$Sd(M) = \sqrt{55.56}= 7.45$

8 0

3 years ago

The lateral area of a right cylinder which has a base diameter of 12 cm and a height of 8 cm is?

garik1379 [7]

Answer:

$A = 301.59\ cm^2$ or $A=96\pi\ cm^2$

Step-by-step explanation:

The lateral area of a cylinder is calculated by the following formula

$A = 2\pi r * h.$

Where r is the radius of the right cylinder and h is the height

In this case we know that the diameter d of the cylinder is

$d=2r\\\\r=\frac{d}{2}\\\\r=\frac{12}{2}\\\\r=6\ cm$

$h=8\ cm$

Therefore the lateral area is:

$A = 2\pi*6 * 8.$

$A = 96\pi$

$A = 301.59\ cm^2$

8 0

3 years ago

Read 2 more answers

Width = (b - a)/n = (8 - 0)/4 = 2

Nookie1986 [14]

Yes, I'm getting C also!

Since it's asking for the left-endpoint Riemann Sum, you will only be using the top left point as the height for each of your four boxes, making -1, -2.5, -1.5, and -0.5 your heights. The bases are all the same length of 2. You don't include f(8) because you're not using right-endpoints, and that would also add another 5th box that isn't included in the 0 to 8 range.

7 0

3 years ago

Read 2 more answers

PLEASE HELP ME SOLVE THESE QUESTIONS<br>IT WOULD BE MUCH APPRECIATED

Ugo [173]

Answer:

1. b.

2. a.

3. b.

4. d.

5. a.

6. b.

7. c.

8. b.

9. b.

10. c.

11. a.

12. b.

13. a.

14. c.

Step-by-step explanation:

7 + 3 = 10

+ 679 - 2056 = -1377

- 398 + 1 = -397

-23 - 237 = 260

2 - 6 = -4

-2 × 3 × -4 = 24

absolute value of -36 = 36

6 + 4 = 10

- 5928 - 965 = -6893

215 × 212 + 212 × 314 = 112148

(15 + 5) ÷ (15 + 5) = 20 ÷ 20 = 1

-457 + 1 = -456

- 218 -1 = -219

6 0

3 years ago