The translation of the sum a and n is a+n
Answer:
...
Step-by-step explanation:
We will turn the left side into the right side.

Use the identity:



Now use the identity
solved for sin^2 x and for cos^2 x.




Answer:
x ≥ 4
Step-by-step explanation:
Since there is a closed circle at x = 4, this indicates that x can be equal to 4
The line to the right is shaded indicating values of x greater than 4
Thus x ≥ 4 ← is the inequality represented in the number line