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vazorg [7]
3 years ago
6

Sarah's craft project uses pieces of yarn that are 1/8 yard long. She has a piece of yarn that is 3 yards long. How many 1/8 yar

d peices can she cut and still have 1 1/4 yards left?
Mathematics
1 answer:
Verdich [7]3 years ago
5 0
If she used all of her yarn, she'd have 24 pieces. If she wanted 1.25 left, she'd have ten less because 24 • .125 = 8, and 1/4 of eight = 2, and 2 + 8 = 10.

So she'd have 14 pieces.
You might be interested in
Order the side lengths from least to greatest
Liula [17]

Answer:

BC < CE < BE < ED < BD

Step-by-step explanation:

In the triangle BCE,

m∠BEC + m∠BCE + m∠CBE = 180°

m∠BEC + 81° + 54° = 180°

m∠BEC = 180 -  135

m∠BEC = 45°

Order of the angles from least to greatest,

m∠BEC < m∠CBE > mBCE

Sides opposite to these sides will be in the same ratio,

BC < CE < BE ----------(1)

Now in ΔBED,

m∠BEC + m∠BED = 180°

m∠BED = 180 - 45

             = 135°

Now, m∠BDE + m∠BED + DBE = 180°

11° + 135°+ m∠DBE = 180°

m∠DBE = 180 - 146

             = 34°

Order of the angles from least to greatest will be,

∠BDE < ∠DBE < ∠BED

Sides opposite to these angles will be in the same order.

BE < ED < BD ----------(2)

From relation (1) and (2),

BC < CE < BE < ED < BD

7 0
3 years ago
How to add the integers -7 and -5.
Rzqust [24]
-7 + -5
When you add negative, it would be the same as subtracting
Turns into: -7-5
-(7+5) = -12
The solutions is -12
8 0
3 years ago
To obtain information on the corrosion-resistance properties of a certain type of steel conduit, 45 specimens are buried in soil
Debora [2.8K]

Answer:

statistic value t= 5.43

p-value: < 0.00001.

Step-by-step explanation:

Hello!

To obtain information over the corrosion-resistance properties of a certain type of steel conduit a random sample of 45 specimens was taken and buried for two years.

The study variable is:

X: Max. penetration of a steel conduit.

The data of the sample

n= 45

sample mean X[bar]= 53.4

sample standard deviation S= 4.2

The conduits are manufactured to have a true average penetration of at most 50 mills, symbolically: μ ≤ 50

The hypothesis is:

H₀: μ ≤ 50

H₁: μ > 50

α: 0.05

To choose the corresponding statistic to use to study the population mean, the variable must have a normal distribution. There is no available information to check this, so I'll just assume that the variable has a normal distribution and, since the population variance is unknown and the sample is small, the statistic to use is a Student t.

Under the null hypothesis, the critical region and the p-value are one-tailed.

Critical value:

t_{n-1; 1-\alpha } = t_{44; 0.95} = 1.68

Rejection rule:

Reject the null hypothesis when t ≥ 1.68

t= \frac{53.4 - 50}{\frac{4.2}{\sqrt{45} } }

t= 5.43

The calculated value is greater than the critical value, thedecision is to rject the null hypothesis.

p-value:

P(t ≥ 5.43) = 1 - P(t < 5.43) = < 0.00001.

The p-value is less than α so the decision is to reject the null hypothesis.

Since the null hypothesis was rejected, then the population average of the penetration of the conduits specimens is greater than 50 mils. It is not recommendable to use these conduits.

I hope it helps!

4 0
3 years ago
What is the answer to this question?
Artemon [7]
The answer is 2143.57mm
5 0
3 years ago
I NEED HELP FAST!!!! 15PTS
Vadim26 [7]
3.option a (-8,2)

4.option b (5,4)
7 0
3 years ago
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