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Andrei [34K]
3 years ago
5

Help pls!

Mathematics
1 answer:
ohaa [14]3 years ago
6 0
JKL is 54 cm. 

JL is 24 cm.
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What is the interquartile range of the data set?
Andrej [43]

Answer:

Should be 10 if there is nothing for th stem value of 3.

Step-by-step explanation:

The stem is the tens place, and the leaf is the ones. You would get 28 40 43 43 45 50 50 for your numbers. If you take Q3-Q1, you get your answer, 10.

7 0
2 years ago
Ally is making a scale diagram of her classroom. She uses a scale factor of 3 centimeters per foot to draw the diagram. The actu
Gnoma [55]
The area of the scale drawing would be 1080 square centimeters or (1080 cm^2). I got this answer through first finding the area of the classroom in feet (which is A= lw = [18][20] = 360 ft^2) and then I proceeded to converting it to centimeters via given scale factor (3 cm = 1 foot) and had the answer of 1080 centimeters squared.
7 0
3 years ago
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Hi can someone help me out with this problem.
elena-s [515]

Answer:

third side = 9

Step-by-step explanation:

Using Pythagoras' identity on the right triangle.

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides.

let the third side be x, then

x² + 40² = 41², that is

x² + 1600 = 1681 ( subtract 1600 from both sides )

x² = 81 ( take the square root of both sides )

x = \sqrt{81} = 9

The third side is 9

3 0
2 years ago
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Find the circumference of a circle rounded to the nearest tenth with a<br> diameter of 4 inches
k0ka [10]

Answer:

12.6

Step-by-step explanation:

Circumference is πd. So...

(3.14*4)

12.56

12.6

Hope this helps and have a nice day ~(^_^)~

8 0
3 years ago
The table shows data from a survey about the number of times families eat at restaurants during a week. The families are either
kifflom [539]

Hey there,

To solve this problem, let us first define what is mean and median. Mean is the average of all the numbers in the data set while the median is the number in the middle of the data set in ascending order. If we create a box plot for the data of Rome and New York, we can see that there is an outlier in the data for New York. Since New York has an outlier, so the mean is not a good representation on the central tendency of the data. The mean is skewed (distorted) by the outlier. So in this case it is better to use the median. While the Rome data is nice and symmetrical, it does not seem to have an outlier,  so we can use the mean for this data set.

Therefore the answer is:

The Rome data center is best described by the mean. The New York data center is best described by the median

Hoped I Helped

6 0
3 years ago
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