Answer:
I was able to get: y = -(6/3)x + 1
Knowing that the line is parallel to another one with equation y = -2x+3, we know that the slope of this line (m) is -2. Plugging this into the point-slope equation
(y-b=m(x-a)), we get y+3=-2(x+4) as our answer.
Step-by-step explanation:
The values of a, b, and c determine the shape and position of the parabola. The domain of a function is the set of all real values of x that will give real values for y. The range of a function is the set of all real values of y that you can get by plugging real numbers into x. The quadratic parent function is y = x2.
X+2y=23
X=-2y +23
Plug this in for x in the second equation
5(-2y + 23) + 10y = 55
-10y + 115 + 10y = 55
The -10y + 10y cancel out, so there is no solution
Hope this helps!