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n200080 [17]
2 years ago
6

Come up with a rule for subtracting integers

Mathematics
1 answer:
erica [24]2 years ago
7 0

Answer: To add integers that have the same sign, keep the same sign and add the absolute value. To add with different signs, keep the sign of the number with the largest absolute value and subtract the smallest absolute valye from the largest.

Step-by-step explanation:

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The Product of a number m and 23​
damaskus [11]

Answer:

23m

Step-by-step explanation:

The product of a number m and the numeral 23 is 23m.

6 0
3 years ago
PLEASE HELP, LAST THING I NEED TO GRADUATE
Mice21 [21]
For a), wouldn't you multiply the cost of a twin by the quantity of a twin beige (N) and the cost of a queen by the quantity of the queen beige (N) and then the cost of the king by the quantity of the king beige (N) for CN and do the same thing but with the south quantities? 
And then for b), it's just comparing which one had the most money and find the difference... 
And then C), would be relatively self explanatory where CN would be the potential profit in N and CS would be the potential profit in S and then CN+CS would be the potential profit total? 

7 0
3 years ago
A square has an area of 9 cm². What is its side length?
Snezhnost [94]

Answer:

3 cm

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
On the coordinate plane below, triangle ABC was rotated
agasfer [191]

Answer: AB/y = BC/z = AC/x

Step-by-step explanation:

Side AB corresponds to side y, side BC corresponds to side z, and side AC corresponds to side x.

7 0
2 years ago
Best answer gets the brainliest!<br> Find $a/b$ when $2\log{(a -2b)} = \log{a} + \log{b}$.
andrey2020 [161]

By some properties of logarithms, rewrite the equation as

2\log(a-2b) = \log(a) + \log(b) \\\\ \log(a-2b)^2 = \log(ab)

so that

(<em>a</em> - 2<em>b</em>)² = <em>ab</em>

Expand the left side:

<em>a</em> ² - 4<em>ab</em> + 4<em>b</em> ² = <em>ab</em>

Rearrange terms to get a quadratic equation in <em>a</em>/<em>b</em> :

<em>a</em> ² - 5<em>ab</em> + 4<em>b</em> ² = 0

<em>b</em> must be greater than 0, otherwise log(<em>b</em>) doesn't exist, and the same goes for <em>a</em>. So we can divide by <em>b</em> ² to get

<em>a</em> ²/<em>b</em> ² - 5<em>a</em>/<em>b</em> + 4 = 0

Factorize and solve for <em>a</em>/<em>b</em> :

(<em>a</em>/<em>b</em> - 4) (<em>a</em>/<em>b</em> - 1) = 0

==>   <em>a</em>/<em>b</em> = 4   or   <em>a</em>/<em>b</em> = 1

However, if <em>a</em>/<em>b</em> = 1, then <em>a</em> = <em>b</em> makes <em>a</em> - 2<em>b</em> = -<em>b</em>. But we must have <em>b</em> > 0, so we omit the second solution and end up with

<em>a</em>/<em>b</em> = 4

5 0
2 years ago
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