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masya89 [10]
3 years ago
8

Using the numbers 5,8, and 24 create a problem using no more than four opperations (add, subtract,multiply,divide,square,squarer

oots,cubed,and cubedroots) where the solution will be an irrational number explain why the results of your opperation is an irrational number.
Mathematics
1 answer:
frez [133]3 years ago
5 0
8 (\sqrt{5} / 24) = 0.7453559924......
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For every 15 minutes of a show, there are two minutes of commercials. At this rate, if Leila has seen 45 minutes of a show, how
Pachacha [2.7K]

Answer:

  51 minutes

Step-by-step explanation:

We have the ratio ...

  show minutes : commercial minutes = 15 : 2

Multiplying by 3 gives ...

  show minutes : commercial minutes = 45 : 6

The total of show minutes and commercial minutes is 45+6 = 51 minutes.

7 0
4 years ago
Students at a school will sell hats to raise money. There are some hats left over from last year, and 20 boxes of hats will be o
inna [77]

Answer:  A) 480

Step-by-step explanation:

x=20 substitute in the two equations

48(20)+37

24(20)+37

since the question said fewer , then you should subtract

48(20)+37 - 24(20)+37 = (960+37) - (480+37)

=923 - 443= 480

4 0
3 years ago
A microwaveable cup-of-soup package needs to be constructed in the shape of cylinder to hold 700 cubic centimeters of soup. The
Korvikt [17]

Answer:

r = 3.43 cm

h=18.94 cm

Step-by-step explanation:

The volume of the cylinder is:

V=\pi r^{2}h=700cm^{3}

where r is the radius of the circular base and h is the height of the cylinder.

The cost of the side of the cylinder is:

(0.02)2\pi rh

The cost ot the bottom of the container is:

(0.02)\pi r^{2}

The cost ot the top of the container is:

(0.09)\pi r^{2}

Then, the total cost of the container is:

C=(0.02)2\pi rh+(0.02)\pi r^{2}+(0.09)\pi  r^{2} \\C=\pi r(0.04h+0.02r+0.09r)\\C=\pi r(0.04h+0.11r)

From the volume, you could solve for one variable and substituting in the cost equation:

h=\frac{700}{\pi r^{2}}\\C=\pi r(0.04(\frac{700}{\pi r^{2}})+0.11r)

In order to minimize this fuction you need to calculate the derivative respect to r:

\frac{dC}{dr} =\frac{dC}{dr}[\frac{28}{r}+0.11\pi    r^{2}]\\\frac{dC}{dr} =-\frac{28}{r^{2} }+0.22\pi  r

The critical points of the function are obtained when dC/dr=0:

-\frac{28}{r^{2}}+0.22\pi  r=0\\0.22\pi r=\frac{28}{r^{2} }\\r^{3}= \frac{28}{0.22\pi } \\r=3.43 cm

To evaluate if this critical point is a minimum, you should get the second derivative:

\frac{d^{2} C}{dr^{2} } =\frac{28}{r^{3} }+0.22\pi \\

For the critical point r = 3.43 cm, the second derivative is positive, which means that the critical point is a minimum.

Then, the dimensions for the package tht will minimize product cost are:

r = 3.43 cm

h=\frac{700}{\pi r^{2}  } =18.94cm

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Answer:

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