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2 years ago

14

Help on all 4 please! The abbreviations are: Side-Side-Side, Side-Angle-Side, Angle-Side-Angle, Angle-Angle-Side

1 answer:

sergiy2304 [10]2 years ago

7 0

Answer:

im pretty sure the answers are

6) c

7) c

8) c

9) a

Step-by-step explanation:

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Meg constructed triangle POQ and then used a compass and straightedge to accurately construct line segment OS, as shown in the f

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In order to understand this question, one needs to understand the construction first. After creating POQ, Meg picks a radius r and makes a circle around O. There are 2 points where the circle meets the triangle. Then, she meets another radius and she makes a circle of radius s around each of the points on the triangle. The two circles cross at one point, as can be seen in the figure. Let's name the first two points A and B and let's name the last point S. We have that for the triangles OAS, OBS we have OA=OB=r, BS=AS=s and that OS is common to both. Thus by the S-S-S triangle equality theorem, the triangles are equal. Hence for the angles AOS=BOS, namely POS=QOS. Since POQ=POS+QOS, we have that POS has to be half of POQ. The only consistent choice is the third one, POS=20 degrees and POQ=40 degrees.

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3 years ago

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A circus tent is cylindrical up to a height of 7 m and is in the shape of a cone over it, the diameter of the cylindrical part i

yan [13]

$\bold{\huge{\underline{ Solution }}}$

<h3><u>Given </u><u>:</u><u>-</u><u> </u></h3>

• The circus tent is composed of cylinder and a cone.

• The height and diameter of the cylindrical part are 7m and 10m

• The total height of the circus tent 19m

• The cost of making the tent at a cost of 35 m² cloth.

<h3><u>Let's </u><u>Begin </u><u>:</u><u>-</u><u> </u></h3>

<u>Here</u><u>, </u><u> </u><u>we </u><u>have </u><u>,</u>

Cylinder and cone
The height and diameter of the cylinder are 7m and 10m
Therefore , radius = 5 m

<u>We </u><u>know </u><u>that</u><u>, </u>

Curved Surface area of the cylinder

$\sf{ = 2{\pi}rh}$

<u>Subsitute the required values, </u>

$\sf{ = 2{\times}3.14{\times}5{\times}7}$

$\sf{ = 6.28 {\times}5{\times}7}$

$\sf{ = 6.28 {\times}35}$

$\bold{ = 219.8m^{2}}$

Thus, The area of the cylinder is 219.8m² .

<h3><u>Now</u><u>, </u></h3>

•We have to find the area of the cone.

•Here, Base of cone = diameter of the cylinder.

•The height of the cone will be

= Height of the tent - Height of cylinder

$\sf{ = 19 - 7 }$

$\bold{ = 12 m }$

<u>We </u><u>know </u><u>that</u><u>, </u>

Area of cone

$\bold{ = {\pi}rl }$

Here, l is the slant height.

Slant height of the cone

$\sf{ = \sqrt{ h^{2} + r^{2}} }$

$\sf{ = \sqrt{ (12)^{2} + (5)^{2}} }$

$\sf{ = \sqrt{ 144 + 25}}$

$\sf{ = \sqrt{ 169}}$

$\sf{ = \sqrt{ 13{\times} 13 }}$

$\bold{ = 13 m }$

Thus, The slant height of the cone is 13 m

<u>Subsitute </u><u>the </u><u>required </u><u>values </u><u>in </u><u>the </u><u>above </u><u>formula </u>

$\sf{ = 3.14 {\times} 5 {\times} 13}$

$\sf{ = 3.14 {\times} 65}$

$\bold{ = 204.1 m^{2}}$

Thus, The area of the cone is 204.1 m² .

<h3><u>Therefore</u><u> </u><u>,</u></h3>

The total area of the circus tent

$\sf{ = 204.1 + 219.8}$

$\bold{ = 423.9m^{2} \: or \: 424 m^{2}}$

<h3><u>Now</u><u>, </u></h3>

We have to find the total cost of making the tent.
The cost for 1 m² = 35

<u>Therefore</u><u>, </u>

The total cost for making the circus tent

$\sf{ = 424 {\times} 35}$

$\bold{ = 14840}$

Hence, The total cost for making the tent is 14840 .

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2 years ago

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Y=18 is the correct answer

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3 years ago

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Which expression is equivalent to 15 + 35

olya-2409 [2.1K]

Answer:

It says “which” so is it multiple choice??

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2 years ago

Solve for v -5v-17>2v+11

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Answer:

Step-by-step explanation:

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2 years ago