Answer:
(-1.1)
Step-by-step explanation:
i dont if is right just tring yo help
C = 6*P
Use that formula and plug in the x-axis values for P and plot the results (C) on the graph
Answer:
1.32% of students have the chance to attend the charter school.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
This year the mean on the entrance exam was an 82 with a standard deviation of 4.5.
This means that ![\mu = 82, \sigma = 4.5](https://tex.z-dn.net/?f=%5Cmu%20%3D%2082%2C%20%5Csigma%20%3D%204.5)
a.What is the percentage of students who have the chance to attend the charter school?
Students who achieve a score of 92 or greater are admitted, which means that the proportion is 1 subtracted by the pvalue of Z when X = 92. So
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![Z = \frac{92 - 82}{4.5}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7B92%20-%2082%7D%7B4.5%7D)
![Z = 2.22](https://tex.z-dn.net/?f=Z%20%3D%202.22)
has a pvalue of 0.9868
1 - 0.9868 = 0.0132
0.0132*100% = 1.32%
1.32% of students have the chance to attend the charter school.
Answer:definition of midpoint, angle BCA is congruent to angle DCA
553,000 is the answer for rounding up