Answer: 
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following:

Complement adds to 90
complement of A is 90-A
supplement is adds to 180
supplemetn of A is 180-A
2(90-A) is -40+180-A
2(90-A)=-40+180-A
2(90-A)=140-A
distribute
180-2A=140-A
add 2A to both sides
180=140+A
minus 140 both sides
40=A
A=40 degres
I believe you just multiply the two numbers together and get 2.665
Answer:
Your answer would be:
Since 6 is in the tenths places, the value of the digit is 0.6
Hope this helps Buddy!
-Courtney