Question

The minimum value of Y in the equation y = x2 - 6x + 8

Answer 1

Given

$y=x^2-6x+8$

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

$y^{\prime}=2x-6$

Equating

$y^{\prime}\text{ = 0}$

gives the minimum value we require.

Doing that, we have:

$2x-6=0$

So that

$\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}$

Therefore, the minimum value is x = 3