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MaRussiya [10]
1 year ago
10

The minimum value of Y in the equation y = x2 - 6x + 8

Mathematics
1 answer:
murzikaleks [220]1 year ago
8 0

Given

y=x^2-6x+8

To obtain the minimum value of y, we first take the derivative of y

The derivative of y is:

y^{\prime}=2x-6

Equating

y^{\prime}\text{ = 0}

gives the minimum value we require.

Doing that, we have:

2x-6=0

So that

\begin{gathered} 2x=6 \\ x=\frac{6}{2} \\ =3 \end{gathered}

Therefore, the minimum value is x = 3

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