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Sveta_85 [38]
4 years ago
6

Find the products. Show your thinking 800×500

Mathematics
2 answers:
wlad13 [49]4 years ago
8 0
The product of 800x500 is 400,000
what i normally do is 8x5, which is 40.
after i get the product, i add all of the zeros.
so, the product of your question is 400,000
LekaFEV [45]4 years ago
5 0
800x500 is4,000 because you multiply 800x500
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After a late night of studying, Ebony decides to grab a latte before class so she can stay awake through her morning lecture. Sh
Rzqust [24]

Answer:

P(Same\ Bill) = \frac{1}{3}

P(Second

P(Both\ Even) = \frac{1}{9}

Pr(One\ Odd) = \frac{4}{9}

P(Sum < 10) = \frac{1}{3}

Step-by-step explanation:

Given

Bills: \$1, \$5, \$10

Selection = 2\ bills

The sample space is as follows:

This implies that we construct possible outcome that Ebony selects a bill, returns the bill and then select another.

This means that there are possibilities that the same bill is selected twice.

So, the sample space is as follows:

S = \{(1,1), (1,5), (1,10), (5,1), (5,5), (5,10), (10,1), (10,5), (10,10)\}

n(S) = 9

Solving (a): P(Same\ Bill)

This means that the first and second bill selected are the same.

The outcome of this are:

Same = \{(1,1),(5,5),(10,10)\}

n(Same\ Bill) = 3

The probability is:

P(Same\ Bill) = \frac{n(Same\ Bill)}{n(S)}

P(Same\ Bill) = \frac{3}{9}

P(Same\ Bill) = \frac{1}{3}

Solving (a): P(Second  < First\ Bill)

This means that the second bill selected is less than the first.

The outcome of this are:

Second < First = \{(1,5), (1,10), (5,10)\}

n(Second < First) = 3

The probability is:

P(Second

P(Second

P(Second

Solving (c): P(Both\ Even)

This means that the first and the second bill are even

The outcome of this are:

Both\ Even = \{(10,10)\}

n(Both\ Even) = 1

The probability is:

P(Both\ Even) = \frac{n(Both\ Even)}{n(S)}

P(Both\ Even) = \frac{1}{9}

Solving (e): P(Sum < 10)

This question has missing details.

The correct question is to determine the probability that, the sum of both bills is less than 10

The outcome of this are:

One\ Odd = \{(1,10), (5,10), (10,1), (10,5)\}

n(One\ Odd) = 4

The probability is:

Pr(One\ Odd) = \frac{n(One\ Odd)}{n(S)}

Pr(One\ Odd) = \frac{4}{9}

 

Solving (d): P(One\ Odd)

This question has missing details.

The correct question is to determine the probability that, exactly one of the bills is 0dd

The outcome of this are:

Sum < 10 = \{(1,1), (1,5), (5,1)\}

n(Sum < 10) = 3

The probability is:

P(Sum < 10) = \frac{n(Sum < 10)}{n(S)}

P(Sum < 10) = \frac{3}{9}

P(Sum < 10) = \frac{1}{3}

 

3 0
3 years ago
Factories ((x+2)+3x+6. 2a(a-1)-a+1​
Wewaii [24]

Answer:1. = 4x+8  

2. 2a²-a+1

Step-by-step explanation:

1. ((x+2)+3x+6.  2. 2a(a-1)-a+1​

((x+2)+3x+6

= x+2+3x+6

= 4x+8

2a(a-1)-a+1

2a²-2a-a+1

2a²-a+1

3 0
3 years ago
I don’t need you to solve anything don’t worry about the numbers but is this triangular prism
igomit [66]

Answer:

This is a triangle prism

Step-by-step explanation:

It definitely can't be rectangle, parallelogram, or trapezoid

4 0
3 years ago
Read 2 more answers
I need to know the answer ASAP
Tomtit [17]

Answer:

2\sqrt{x} is valid for all values of x ≥ 0

Step-by-step explanation:

4 0
3 years ago
Find the 64th term of the arithmetic sequence
Margaret [11]

Answer:

The 64th term of the arithmetic sequence is -1075.

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms, called common difference, is always the same.

The nth term of an arithmetic sequence is given by:

a_n = a_1 + (n-1)d

In which a_1 is the first term.

−4,−21,−38

First term -4, so a_1 = -4

Common difference of d = -38 - (-21) = -21 - (-4) = -17

Thus

a_n = a_1 + (n-1)d

a_n = -4 - 17(n-1)

Find the 64th term of the arithmetic sequence

This is a_{64}. So

a_n = -4 - 17(n-1)

a_{64} = -4 - 17(64-1) = -4 - 1071 = -1075

The 64th term of the arithmetic sequence is -1075.

8 0
3 years ago
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