Answer:
B. y = tan x and C. y = cot x
Step-by-step explanation:
Range:
range is defined as the set of values that any given function y=f(x), can take for which the x values are defined. It is the value that y can take for the values of x.
Given:
From the given options
the range of tanx and cotx are all real numbers
as the period of tanx and cotx are π
where as range of secx is all real numbers except π/2 + n*π i.e.
(-∞ , -1] U [1 , + ∞)
And range of cscx is all real numbers except n*π i.e.
(-∞ , -1] U [1 , + ∞)
So from the given option:
option B and C are correct while A and D are not !
Answer:
To solve an exponential equation, take the log of both sides, and solve for the variable.
Step-by-step explanation:
Example 1: Solve for x in the equation tex2html_wrap_inline119 .
Solution:
Step 1: Take the natural log of both sides:
displaymath121
Step 2: Simplify the left side of the above equation using Logarithmic Rule 3:
displaymath123
Step 3: Simplify the left side of the above equation: Since Ln(e)=1, the equation reads
displaymath127
Ln(80) is the exact answer and x=4.38202663467 is an approximate answer because we have rounded the value of Ln(80)..
Check: Check your answer in the original equation.
displaymath131
Answer:
x=12 and
(9*12)-10=98
(5*12)+38=98
both angles are = 98
Step-by-step explanation:
do this :
9x - 10 = 5x + 38
( - 5x from both sides)
4x - 10 = 38
(add 10 to both sides)
4x = 38+10
4x=48
(divide by 4)
x=48/4
= 12
substitute into the equations:
(9*12)-10
(5*12)+38
Answer:
- -2/a³ m/s
- -2 m/s
- -1/4 m/s
- -2/27 m/s
Step-by-step explanation:
The velocity is the derivative of position:
v = ds/dt = (d/dt)(t^-2) = -2t^-3
For t=a, the velocity is
-2a^-3 = -2/a³ . . . . meters per second
For t=1, the velocity is ...
-2·1³ = -2 . . . . meters per second
For t=2, the velocity is ...
-2·2^-3 = -2/8 = -1/4 . . . . meters per second
For t=3, the velocity is ...
-2·3^-3 = -2/27 . . . . meters per second
