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Stels [109]
2 years ago
13

Will give brainliest need help asap! pls :)

Mathematics
1 answer:
Ymorist [56]2 years ago
4 0

Answer:

0.0001t^3-0.016t^2+0.21t+7.4

Step-by-step explanation:

I just added the equations for F and M together.

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Plz help!! One question Im stuck on.
kolezko [41]
I think you could do is 9 squared + 12 squared = x squared 
the 81+144=225 
and the square root of 225 is 15

lets just say the answer you are looking for is 15



3 0
2 years ago
Read 2 more answers
which expense is considered a fixed, discretionary expense? a. car loan payment b. grocery bill. c. music subscription service f
aliya0001 [1]

Answer:

c. music subscription service fee

Step-by-step explanation:

A discretionary expense is an expense you (or your family) can life without if it is required. A fixed expense is a period-specif expense, which means is and expense you paid over a fix time.  

If you think about, the definition of "fixed, discretionary expense" fits an entertainment subscription perfectly; therefore a music subscription service fee is a fixed, discretionary expense.

4 0
2 years ago
Describe the main parts of a proof.
Lorico [155]

Answer:

The main parts of a proof are the statements and the reasons. The statements are things you want to prove, and the reasons are the justifications for the statements. Some parts of a proof will provide a given statement or a visual with some congruency

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Write &lt;,&gt; or =<br> 11.11_____ 11.19 with
Alisiya [41]

Answer:

11.11 < 11.19

Step-by-step explanation:

11.11 is less than (<) 11.19 by 0.08

11.19 - 11.11 = 0.08

~

6 0
3 years ago
a large number of voltages show a mean of 118.5v and a population standard deviation of 1.20v. determine the percentage of data
Musya8 [376]

Answer:

Step-by-step explanation:

Hello!

X: voltage, it has a mean of μ= 118.5V and a standard deviation of σ= 1.20V.

Assuming the variable has a normal distribution, I'll use the standard normal distribution to calculate the probability that the voltage is between 116 and 120 volts.

P(116≤X≤120) = P(X≤120) - P(X≤116)

Using Z= (X - μ)/σ you now standardize the voltage values and get the cumulative probabilities from the tables of Z.

P(Z≤(120-118.5)/1.20) - P(Z≤(116-118.5)/1.20)

P(Z≤1.25) - P(Z≤-2.08)= 0.89435 - 0.01876= 0.87559

87.559% of the data will be between 116 and 120 volts.

I hope you have a SUPER day!

8 0
3 years ago
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