This is a 2 answer question
1 answer:
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Answer:
Step-by-step explanation:
<u>Slope-intercept </u><u>form</u>
y= mx +c, where m is the slope and c is the y-intercept
Line p: y= -8x +6
slope= -8
The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.
m(-8)= -1
m= -1 ÷(-8)
m= ⅛
Substitute m= ⅛ into the equation:
y= ⅛x +c
To find the value of c, substitute a pair of coordinates that the line passes through into the equation.
When x= 2, y= -2,
-2= ⅛(2) +c
Thus, the equation of line q is .
Given:
The system of equations:
To find:
The number that can be multiplied by the second equation to eliminate the x-variable when the equations are added together.
Solution:
We have,
...(i)
...(ii)
The coefficient of x in (i) and (ii) are 1 and respectively.
To eliminate the variable x by adding the equations, we need the coefficients of x as the additive inverse of each other, i.e, a and -a So, a+(-a)=0.
It means, we have to convert into -1. It is possible if we multiply the equation (ii) by -5.
On multiplying equation (ii) by -5, we get
...(iii)
On adding (i) and (iii), we get
Here, x is eliminated.
Therefore, the number -5 can be multiplied by the second equation to eliminate the x-variable.