The domain is the set of allowed x inputs, or x coordinates of a function. In this case, any point on the curve has an x coordinate that is 4 or smaller.
Therefore, the domain is the set of numbers x such that
To write this in interval notation, we would write
This interval starts at negative infinity and stops at 4. We exclude infinity with the curved parenthesis and include 4 with the square bracket.
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The range is the set of possible y outputs. Every point on this curve has a y coordinate that is either 0 or it is larger than 0.
The range is the set of y values such that 
In interval notation, it would be written as
This time we start at 0 (including this endpoint) and "stop" at infinity
note: we always use curved parenthesis at positive or negative infinity because we cannot reach either infinity
Answer:
253.48
Step-by-step explanation:
Hello this is answer
Answer:
huh????
Step-by-step explanation:
Answer:
6.3 kilograms
Step-by-step explanation:
Because 1 kilo is 2.2 pounds, divide 13.86 pounds by 2.2 to get 6.3 kilograms
Answer:
- Solution of equation ( q ) = <u>1</u><u>6</u>
Step-by-step explanation:
In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>
<u>Solution : -</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

On further calculations we get :

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

On further calculations we get :

- <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>equation</u><u> </u><u>(</u><u> </u><u>q </u><u>)</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
Now we are very our answer by substituting value of q in the given equation . So ,
<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>