1. Cross multiply
35x = 5(11)
35x = 55
Divide both sides by 35
x = 55/35
x = 11/7

2. (x - 2)/x = 3/8
Cross multiply
3x = 8(x - 2)
3x = 8x - 16
Subtract 8x from both sides
-5x = -16
divide both sides by -5
x = -16/-5
x = 16/5 OR 3 1/5

3. (a + 1)/(a - 1) = 5/6
cross multiply
6(a + 1) = 5(a - 1)
distribute
6a + 6 = 5a - 5
subtract 5a from both sides
a + 6 = -5
subtract 6 from both sides
a = -11

4. (1/3)x - 4 = (2/3)x + 6
multiply each term by 3 to clear the fractions
x - 12 = 2x + 18
subtract x from both sides
-12 = x + 18
subtract 18 from both sides
-30 = x

3 0

3 years ago

The vector ~v represents the displacement vector from Portland, Oregon to Houston, Texas. The vector w~ represents the displacem

Art [367]

Answer:

the displacement of the plane is $- \= w$

The displacement of plane from Portland to Akron with layover at Houston is

$\= v + \= w$

the vector which defines this displacement is $\= v + \= w =- 2500 \ km$

Step-by-step explanation:

From the question we are the

The displacement from Portland, Oregon to Houston, Texas. is $\= v$

The displacement from Houston, Texas to Akron, Ohio. is $\= w$ a

The motion of the plane in question a is in the opposite direction to vector $\= w$

So the displacement of the plane is $- \= w$

The motion of Portland to Houston to Akron is in the direction of both vector $\= v$ and $\= w$ so

The displacement of plane from Portland to Akron with layover at Houston is

$d = \= v + \= w$

From the question we are told that the plane flies over Portland to get to Anchorage, Alaska which implies that it is moving in opposite direction to the vector $\= v$

Give that distance from Portland to Houston is $\= v = 3000 km$