Don't get confused by the "0.01 cm" that's just telling you to round to the hundredths place. Moving on, the shaded area's exterior shows us that it is a square. Meaning you do s^2 to find the area. So, you find the square root of 15 which is <span>3.87... This means the diameter is also 3.87 because the diameter is equivalent to the side's measurement. Divide 3.87 by 2 to find the radius, giving you 1.935. This represents OT's length. Now, just round to the hundredths giving you 1.94 cm. </span>
Answer:
The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Step-by-step explanation:
There are a total of <em>N</em> = 25 aluminum castings.
Of these 25 aluminum castings, <em>n</em>₁ = 4 castings are defective (D) and <em>n</em>₂ = 21 are good (G).
It is provided that a quality control inspector randomly selects three of the twenty-five castings without replacement to test.
In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.
The formula to compute the combinations of k items from n is given by the formula:

Compute the number of samples that are possible as follows:


The sample space for selecting the group to test contains <u>2,300</u> elementary events.
Answer:
yes
Step-by-step explanation:
100-75=25% did not like
25%=35 students how about 75%
75 x 35 divided by 25=105 students
105
Answer: 0.4758
Step-by-step explanation:
Given : Mean : 
Standard deviation : 
Also, the new population of pilots has normally distributed .
The formula to calculate the z-score :-

For x=130 lb .

For x=171lb.

The p-value =

Hence, the required probability : 0.4758