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hoa [83]
2 years ago
12

What is the greatest common factor of 9x^2y and 5x^4y^2

Mathematics
1 answer:
ELEN [110]2 years ago
6 0
Xy(9x)(5x^3y) so the greatest common factor is xy 
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Which expression is equivalent -21.8-(-18.3)
navik [9.2K]
<span> -21.8-(-18.3) (2 negative signs become positive)
=</span><span> -21.8 + 18.3
= - 3.5

Answer
- 3.5</span>
3 0
3 years ago
Read 2 more answers
Brainliest + Points!<br><br> Please explain !
Morgarella [4.7K]

Answer:

A) -2/5

Step-by-step explanation:

Note that for a slope, the slope of the line is found by using the equation:

slope = (rise/run).

In this case, find two points. For example, i will use:

(0, 2) & (5, 0). (x = 0, y = 2) ; (x = 5, y = 0)

Note that "rise" = y, and "run" = x. Plug in the corresponding numbers for the corresponding points.

(2 - 0)/(0 - 5) = slope

Simplify

(2)/(-5) = slope

-(2/5) is your answer.

Note that it does not matter where the negative sign is placed.

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6 0
3 years ago
If line GH is perpendicular to line HJ, then GJ is ____ HJ.
valentinak56 [21]

Option A: >

Solution:

Given a triangle GHJ.

The line GH is perpendicular to line HJ.

This means the triangle is a right angled triangle.

In ΔGHJ, GH is the base of the triangle and

HJ is a height of the triangle.

Then the third side must be the hypotenuse of the right triangle.

We know that by the Pythagoras theorem,

(\text {Hypotenuse})^2=(\text{Base})^2+(\text{Height})^2

(\text {GJ})^2=(\text {GH})^2+(\text {HJ})^2

This clearly shows that the hypotenuse is greater than the height.

⇒ GJ > HJ

Option A: > is the correct answer.

If line GH is perpendicular to line HJ, then GJ is > HJ.

3 0
3 years ago
Solve equation 1/4=x^-1/2
Alex

Answer:

A. {16}

Step-by-step explanation:

1/4 = x^-1/2

We have the exponent rule a^-1 = 1/a^1

Applying the rule, we get

1/4 = 1/x^1/2

x^1/2 = √x

1/4 = 1/√x

Now let's cross multiplying, we get

√x  = 4

Taking square on both sides, we get

x = 16

The answer: A. {16}

Hope this will helpful.

Thank you.

3 0
3 years ago
Read 2 more answers
HELP CALCULUS 25 POINTS
shepuryov [24]

Answer:

A.) Max at x = 6 and Min at x = -6

Step-by-step explanation:

We say that f(x) has a relative (or local) maximum at x=c if f(x)≤f(c) f ( x ) ≤ f ( c ) for every x in some open interval around x=c . We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on.

4 0
3 years ago
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