What is the rate of change of the function?
2 answers:
Answer:
-2
Step-by-step explanation:
Rise over run
Pick a point and check how much it goes vertically, then divide it by how much it goes horizontally.
Answer:
Option A
Step-by-step explanation:
The given function is a linear function therefore rate of change of this function will be the slope of the given line.
Since this line passes through two points ( 0,1 ) and ( 0.5 0 )
the slope of the line = 
slope = 
= ( -2 )
Therfore, Option A will be the answer.
You might be interested in
Answer:64
Step-by-step explanation:
You have the other 3 box's with 20 left which is 60 so all you gotta do is 20-16 which is 4
Answer:
Step-by-step explanation:
The answer is 1/27
due to
(1/3)^3 = [(1)^3]/[3^3] =1/27
Best regards
A. 10g4h9
-5gh4(-2g3h5)
(-5 x -2)= 10
(g x g3)=g4
(h4 x h5)= h9
= 10g4h9
Find the slope m.
Use the point-slope formula.
Solve for y.

Explanation

Step 1
multiplicate by the conjugate

notice that


I hope this helsp you