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xz_007 [3.2K]
3 years ago
12

What ratios is equivalent to 36:60

Mathematics
1 answer:
ludmilkaskok [199]3 years ago
3 0
3:5
6:10
This should be some.
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What's the equation to solve this? Can't remember!
Lerok [7]
Arc SCD is two times of angle SED, so arc SCD is 8x+22. Now set 8x+22, 5x-8, and 11x+10 to 360 and solve for x
7 0
3 years ago
A seamstress is paid $9.55 for every pair of pants made. how many pants would have to be made to receive $525.00 a week?
Svetlanka [38]
Let the number of pants have to be made be x.

So,

9.55 * x = 525.00

x = \frac{525}{9.55} ≈ 54.97 

Thus, the number of pants have to be made are 54.
8 0
3 years ago
Find the midpoint of points A(8,-7) and B(3,-1) graphically
sukhopar [10]

Answer: (5.5, -4)

Step-by-step explanation:

You can use the midpoint formula to find the midpoint of point A and point B.

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

x₁ = 8

x₂ = 3

y₁ = -7

y₂ = -1

M(\frac{x_{1}+x_{2} }{2}, \frac{y_{1} + y_{2} }{2})

M(\frac{8+3 }{2},  \frac{-7 +-1}{2} )

M(\frac{8+3 }{2},  \frac{-7 -1}{2} )

M(\frac{11 }{2},  \frac{-8}{2} )

M(5.5, -4 )

Midpoint = (5.5, -4)

Hope this helps!

3 0
3 years ago
Equivalent answers for 64 to the power of 2/3
madreJ [45]

Answer:

16

Step-by-step explanation:

Dealing with a fraction exponent on hand can be converted by using the fractional exponents rule where the fraction exponent is converted to something like this:

64^\frac{2}{3} = \sqrt[3]{64^{2}}\\

As you can see, the denominator of the fractional exponent is now the index of the radical. Here is a guide to know what goes where.

64^\frac{x}{y} = \sqrt[y]{64^{x}}

Both the original problem (64^2/3) and the converted formula can be put into a calculator.

<u>Simplify (if you want to)</u>

<u />\sqrt[3]{64^{2}}\\\sqrt[3]{4096}\\16<u />

<u />

64 to the power of 2/3 is 16.

5 0
3 years ago
A thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F. Af
fgiga [73]

Answer:

53.3324

Step-by-step explanation:

given that a  thermometer is removed from a room where the temperature is 70° F and is taken outside, where the air temperature is 40° F.

By Newton law of cooling we have

T(t) = T+(T_0-T)e^{-kt}

where T (t) is temperature at time t,T =surrounding temperature = 40, T0 =70 = initial temperature

After half minute thermometer reads 60° F. Using this we can find k

T(0,5) = 40+(70-40)e^{-k/2} = 60\\e^{-k/2} =2/3\\-k/2 = -0.4055\\k = 0.8110

So equation is

T(t) = 40+(30)e^{-0.8110t}\\

When t=1,

we get

T(1) = 40+(30)e^{-0.8110}\\\\=53.3324

5 0
3 years ago
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