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cluponka [151]
3 years ago
13

There are 8 distinct points on a plane, where no three are collinear. An insect starts at one of these points, and walks in a st

raight line to another point, and continues doing this until it reaches all 8 points, creating 7 segments. What is the maximum amount of times the insect crosses its own path? - Will give Brainliest
Mathematics
1 answer:
Sauron [17]3 years ago
4 0

Answer:

Total Number of lines will be 28

Step-by-step explanation:

We can use combinations to solve this question.

Let the two Collinear points be denoted by A and B and the other other points be denoted by x1,x2,x3,x4, x5 and x6.

Suppose that only A and B are collinear.

The number of lines determined by any two of x1 to x6  are given by 6C2= 15

The number of lines from A or B and x1---x6 is given by 6C1 * 2C1= 12

The number of lines from A to B is 1.

Total Number of lines = 15+ 12+ 1= 28

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Answer:

The interval is constructed at 93% confidence.

Step-by-step explanation:

Confidence interval concepts:

A confidence interval has two bounds, a lower bound and an upper bound.

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Confidence interval of proportions concepts:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

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In this problem, we have that:

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Upper bound: 0.903

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Confidence level:

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