Answer:

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795
Step-by-step explanation:
Given
See attachment for class
Solving (a): Fill the midpoint of each class.
Midpoint (M) is calculated as:

Where
Lower class interval
Upper class interval
So, we have:
Class 63-65:

Class 66 - 68:

When the computation is completed, the frequency distribution will be:

Solving (b): Mean and standard deviation using 1-VarStats
Using 1-VarStats, the solution is:


<em>See attachment for result of 1-VarStats</em>
Answer:
<h3>Option C. 6 : 1 is the answer.. </h3>
<h2>Hope it can help you and please mark me as a brainlist..</h2>
Answer:
6 months
Step-by-step explanation:
Your answer from smallest to largest is:
3/10
3/5
13/20
22/25
To get your answer, you will need to find the perpendicular slope for -1/3x which is just the opposite therefore it will be 3x. Your slope is 3x as perpendicular so use this slope to do point slope. Y-1=3(x-2). Distribute y-1=3x-6. Add 1 to both sides. (-1+1) (-6+1)=-5. So your equation in slope intercept form is y=3x-5. Going through the two points.
Hope this helps!