3 years ago

Are 6/10 and 6/30 multiples of 3/10

2 answers:

7 0

10 is not a multiple of 3 so no 6/10 is not multiples for 3/10 and 6 is not a mutiple of 10 so it can't be also the same with 6/30 although 6/30 is multiples for 3 but 6 is not a mutiple for 10.

Aleksandr [31]3 years ago

4 0

10 is not a multiple of 3 so no 6/10 and 6/30 are not multiples of 3/10

You might be interested in

Find the value of this expression if x = 2 and<br> y= 1.

N76 [4]

Answer: 2/5

Step-by-step explanation:

xy^2

--------

If x = 2 and y = 1

x * y^2 2 × 1^2

----------- -----------

5 5

---

6 0

3 years ago

Let f(x) = x – 3 and g(x) = x + 11. Find f(x) • g(x).. . A] x2 – 8x – 33. . B] x2 – 8x + 14. . C] x2 + 8x + 14. . D] x2 + 8x – 3

Katarina [22]

F(x) = x-3 and g(x) = x+11

f(x) *g(x) = (x-3)(x+11) = x^2 +11x -3x -33 = x^2 +8x -33

so choice D. is right

hope helped

3 0

3 years ago

Read 2 more answers

Find −14(5).

erica [24]

Answer:

-14(5) = -70

9(-12) = -108

-6(-8) = 40

ab = -16(-5) = 80

6 0

2 years ago

Perimeter and Area Geometry help, please don't comment if you aren't 100% sure. Will give Brainliest and upvote

miskamm [114]

216 as it is the only one 6 divides into

3 0

3 years ago

Read 2 more answers

To estimate the length of the lake, caleb starts at one end of the lake and walk 95m. He then turns a 60° angle and walks on a n

aivan3 [116]

Answer:

Length of the lake is 97.30 m

Step-by-step explanation:

We have given Caleb starts at one end of the lake and walk 95 m

So $d_1=95m$

And then he turns at an angle of 60°

So $\Theta =60^{\circ}$ and then again walk 8 m

So $d_2=8m$

We have to fond the total length of the lake , that is d

Total length of the lake is given by $d=\sqrt{d_1^2+d_2^2+2d_1d_2cos\Theta }=\sqrt{95^2+8^2+2\times 95\times 8\times cos60^{\circ}}=97.30m$

So length of the lake is 97.30 m

3 0

2 years ago