Let f and g be differentiable functions such that f(1) = 2, f'(1) = 3, f'(2) = -4, g(1) = 2, g'(1) = -3, g'(2) = 5. If h(x) = f
(g(x)) , then h'(1) =
1 answer:
Answer:
12
Step-by-step explanation:
h(x) = f(g(x))
Using chain rule:
h'(x) = f'(g(x)) g'(x)
h'(1) = f'(g(1)) g'(1)
h'(1) = f'(2) g'(1)
h'(1) = -4 × -3
h'(1) = 12
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