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3 years ago

5

Let f and g be differentiable functions such that f(1) = 2, f'(1) = 3, f'(2) = -4, g(1) = 2, g'(1) = -3, g'(2) = 5. If h(x) = f

(g(x)) , then h'(1) =

1 answer:

crimeas [40]3 years ago

7 0

Answer:

12

Step-by-step explanation:

h(x) = f(g(x))

Using chain rule:

h'(x) = f'(g(x)) g'(x)

h'(1) = f'(g(1)) g'(1)

h'(1) = f'(2) g'(1)

h'(1) = -4 × -3

h'(1) = 12

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