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Rufina [12.5K]
3 years ago
9

The population of a rabbit colony triples each month.

Mathematics
1 answer:
djverab [1.8K]3 years ago
3 0

Answer:

3645 rabbits after 6 months.

Step-by-step explanation:

The population of a rabbit colony triples each month.

This means that the population of the colony after t months is given by:

P(t) = P(0)(3)^t

In which P(0) is the initial population.

The population started with 5 rabbits.

This means that P(0) = 5

So

P(t) = 5(3)^t

How many rabbits are there after 6 months?

This is P(6). So

P(6) = 5(3)^6 = 3645

3645 rabbits after 6 months.

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EAB and DCB are two right triangles. The figure has BED≅ BDE. Point B is the midpoint of segment AC. Prove: EAB≅ DCB
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See the attached picture. 

<span>you are given that ABCE is an isosceles trapezoid. </span>

<span>you are given that AB is parallel to EC. </span>

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<span>you are given that AE and AD are congruent. </span>

<span>triangle EAD is an isosceles triangle because AE and AD are congruent. </span>

<span>this means that angle 1 is equal to angle 3. </span>

<span>since angle 1 is equal to angle 2 and angle 3 is equal to angle 1, then angle 3 is also equal to angle 2. </span>

<span>this means that AD and BC are parellel because their corresponding angles (angles 3 and 2) are equal. </span>

<span>since AB is parallel to EC and DC is part of the same line, than AB is parallel to DC. </span>

<span>you have AB parallel to DC and AD parallel to BC. </span>

<span>if opposite sides of a quadrilateral are parallel, then the quadrilateral is a parallelogram. </span>

<span>that might be able to do it,depending on whether all these statements are acceptable without proof. </span>

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5 0
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What is the correct equilibrium constant expression for this equation? 2 upper C upper o upper F subscript 2 (g) double arrow up
Alekssandra [29.7K]

The correct equilibrium constant expression for this equation is;

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Consider the equation below.

\rm {2COF_2(g)}\rightleftharpoons C0_2(g)+CF_4(g)

<h3>What are Species?</h3>

In an equilibrium constant expression, you do not include the solid substances; only gases and dissolved substances.

<h3>Equilibrium constant expression;</h3>

It is the quotient of the product of the concentrations of the species on the right-hand side of the equilibrium equation, each raised to its corresponding coefficient, and the product of the concentrations of the species on the left-hand side, each raised to its corresponding coefficient.

Therefore,

The correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}

Hence, the correct equilibrium constant expression for this equation is;

\rm K_{eq}=\dfrac{(C0_2)(CF_4)}{(COF_2)^2}.

To know more about Equilibrium constant click the link is given below.

brainly.com/question/19240570

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