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poizon [28]
3 years ago
6

How to simplify 10P6/10P4

Mathematics
1 answer:
PSYCHO15rus [73]3 years ago
6 0

nPk=\dfrac{n!}{(n-k)!}\\\\ \dfrac{ 10P6}{10P4}=\dfrac{\dfrac{10!}{4!}}{\dfrac{10!}{6!}}=\dfrac{10!}{4!}\cdot\dfrac{6!}{10!}=5\cdot6=30

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Rosa wants 2 pairs of jeans that cost $32 each .she has a coupon for $10 off the price of one pair .what price will rosa pay for
Phoenix [80]

Answer:

$54

Step-by-step explanation:

An expression for the total cost would be:

1($32) + ($32-$10) = $32 + $22 = $54

8 0
4 years ago
The Hurry-Mart convenient store is re-stocking their shelves. They always stock the m&m to Hershey bars at a ratio of 10 to
castortr0y [4]

Answer:

12 Hershey bars

Step-by-step explanation:

if its 10 to 8 and you have 15 m&m then you would have to do the 10 which you would have to put 8 then 5 is half of 10 so you would just half 8 which is 4 so 8+4+12. 12 Hershey bars needed to restock the shelf.

8 0
3 years ago
Plz Helppp meeee assapppp
Gwar [14]

Given:

A right angled triangle.

To find:

The value of x.

Solution:

We have,

Base = x

Hypotenuse = \sqrt{5}

In a right angle triangle,

\cos \theta = \dfrac{Base}{Hypotenuse}

For the given triangle,

\cos 45^\circ= \dfrac{x}{\sqrt{5}}

\dfrac{1}{\sqrt{2}}= \dfrac{x}{\sqrt{5}}

Multiply both sides by \sqrt{5}.

\dfrac{\sqrt{5}}{\sqrt{2}}= x

\dfrac{\sqrt{5}}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}= x

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Therefore, the required value of x is \dfrac{\sqrt{10}}{2}.

8 0
3 years ago
1. A number is 6 more than the average of, its half, its one-third and its one sixth
stira [4]

Answer:

let no.be x

its half= x/2

its one third= x/3

its one sixth=x/6

atq.....avg of x= x/2+x/3+x/6//3=6x/6//3=x/3

now...x/3+6=x...as the no.is 6 more than its avg

x= 9

7 0
3 years ago
Fifteen students were divided into two classrooms in a ratio of 1:2.
IgorC [24]
The answer: In Classroom 1, there are 5 students while in Classroom 2, there are 10 students.

Explanation:
x + 2x = 3x
3x = 15
x = 5, Classroom 1 = 5, Classroom 2 = 5 x 2 = 10

I hope that this helps! :)
3 0
2 years ago
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