N + 6f (n = 9 and f= 3)
1 answer:
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Answer:
{-2/3, 2/3, 3}
Step-by-step explanation:
The equation can be factored by grouping.
f(x) = (9x^3 -27x^2) +(-4x +12)
f(x) = 9x^2(x -3) -4(x -3)
f(x) = (9x^2 -4)(x -3)
We recognize the first factor as the difference of squares, so know it can be further factored to give ...
f(x) = (3x -2)(3x +2)(x -3)
The zeros are the values of x that make these factors be zero:
3x -2 = 0 ⇒ x = 2/3
3x +2 = 0 ⇒ x = -2/3
x -3 = 0 ⇒ x = 3
The zeros of the polynomial are x = -2/3, 2/3, 3.
Answer:
Step-by-step explanation:
a. 9(4x - 3y - )
36x - 27y - ( *
)
36x - 27y -
36x - 27y - 6
b. -2 (-6x + 3y - 1)
12x - 6y + 2
c. (20y - 4x - 13)
4y - x -
- x + 4y -
d. 8(-x - )
-8x - 4
e. -8(-x - y +
)
8x + y -
8x + 6y - 28
Hope that helps!