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3 years ago

What is 2.685 rounded to the nearest hundredths place

Mathematics

2 answers:

RoseWind [281]3 years ago

7 0

The answer is: 2.69

Bingel [31]3 years ago

3 0

2.685 rounded to the nearest hundred is 2.69.

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A group of farmers planted 62 fields of vegetables. of the fields they planted, 4/5 were planted with cabbage. how many fields o

chubhunter [2.5K]

Total number of fields of vegetables = 62

Thus,

The amount of fields that is cabbage = $\frac{4}{5} * 62 = \frac{248 }{5} = 49.8$

4 0

3 years ago

In 1985, there were 285 cell phone subscribers in Arlington. The number of subscribers increased by 75% per year since 1985. Fin

ANTONII [103]

Answer:

The number of subscribers in 2008 is 110,845,988

Step-by-step explanation:

The number of cell phone subscribers in Arlington, in t years after 1985, can be modeled by the following equation.

$N(t) = N(0)(1+r)^{t}$

And which N(0) is the number of subscribers in 1985 and r is the rate it increases per year, as a decimal.

In 1985, there were 285 cell phone subscribers in Arlington.

This means that $N(0) = 285$

The number of subscribers increased by 75% per year since 1985.

This means that $r = 0.75$

$N(t) = 285(1.75)^{t}$

Find the number of subscribers in 2008.

2008 is 2008-1985 = 23 years after 1985. So we have to find N(23).

$N(23) = 285(1.75)^{23} = 110,845,988$

The number of subscribers in 2008 is 110,845,988

8 0

3 years ago

If there are 3 classrooms that each have 25 desks and there are a total of 87 students, how many more desks need to be added to

Reptile [31]

Answer:

Step-by-step explanation:

If there are 3 classrooms that each have 25 desks and there are a total of 87 students, how many more desks need to be added to a 4th classroom, that was originally empty, so that each of the students has a desk to sit in?

25 * 3 = 75

87 - 75 = 12

5 0

3 years ago

12 seventy fifths written as a decimal

kakasveta [241]

Do you mean the #12 and severe to fifths to a decimals if you are then it's 12.57

3 0

3 years ago

If u = -8i + 7j, what is the magnitude of -5u? Simplify any radicals.

lubasha [3.4K]

Answer:

$- 5 \sqrt{113}$

Step-by-step explanation:

Find the magnitude of the complex number

Notice the magnitude is equal to

$u = \sqrt{ {a}^{2} + {b}^{2} }$

where a is the real number and b is the imaginary number.

Substitute

$u = \sqrt{ - 8 {}^{2} + 7 {}^{2} }$

$u = \sqrt{64 + 49}$

$u = \sqrt{113}$

Multiply this by -5

$- 5 \sqrt{113}$

7 0

2 years ago