2a+3c=56, a+4c=49.50
2a+3c=56.00
-2(a+4c=49.50)
_______________
2z+3c=56
-2a-8c=99
____________
0+-5c=-43
-5c=-43
c= -43/-5
child ticket=8.60
now take c and plug the answer into the first equation: 2a+3c=56, 2z+3(8.60)=56, 2z+25.80=56, 2a=56-25.80, 2a= 30.20, a=30.20/2, adult tickets =15.10
Answer:
There would be 1 tile in Figure 0.
nah mas sumas todas las medidas
<u><em>Moe Larry</em></u>
<u><em>35 + 20x 60 + 10x</em></u>
<u><em></em></u>
<u><em>35 + 20x = 60 + 10x</em></u>
<u><em>(show work)</em></u>
<u><em>x = 2.5</em></u>
<u><em></em></u>
<u><em>Moe and Larry will have the same amount of money in their savings accounts after 2.5 weeks.</em></u>
<u><em>-From TheRealMarinette</em></u>
<u>-Pls Dont Not Copy N Paste.</u>
you will have to do letter c witch was:
Step 1: Add the price of the tickets and the amount spent on food.
Step 2: Add the amount of the tax.
Step 3: Divide that total by 2.