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mezya [45]
2 years ago
10

A newspaper reporter says that a company made 700,000 profit last year it says this was 12% more then the year before . Work out

how much profit the company made the year before
Mathematics
1 answer:
Dmitriy789 [7]2 years ago
4 0

Answer:

625000

Step-by-step explanation:

x+12%= 700000

x*1.12=700000

x=700000/1.12

x=625000

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Write an expression for 40% of 25
Montano1993 [528]

For this case we must find an expression to find 40% of 25. So, we make a rule of three:

25 -----------> 100%

x -------------> 40%

Where "x" represents the amount that determines 40% of 25.

x = \frac {40 * 25} {100}\\x = 10

40% of 25 is 10. And an expression to find it is:

x = \frac {40 * 25} {100}

Answer:

x = \frac {40 * 25} {100}


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3 years ago
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Sum of one-half of a number and 4 is -16. find the number
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sum of half a number and 4 means
(x/2)+4
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(x/2)+4=-16
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A flock of griffins are flying together along the same route as the dragons. Griffins have the head and wings of an eagle, but t
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Asked and answered elsewhere.
brainly.com/question/9446189
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Simplify 7d+12-14d-3
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3 years ago
Evaluate the following integral using trigonometric substitution.
wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function \int\limits {\sqrt{a^{2} -x^{2} } } \, dx, using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as asin \theta i.e x = a sin\theta.

All integrals in the form \int\limits {\sqrt{a^{2} -x^{2} } } \, dx are always evaluated using the substitute given where 'a' is any constant.

From the given integral, \int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx where a = 7 in this case.

The substitute will therefore be   x = 7 sin\theta

2.) Given x = 7 sin\theta

\frac{dx}{d \theta} = 7cos \theta

cross multiplying

dx = 7cos\theta d\theta

3.) Rewriting the given integral using the substiution will result into;

\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta  } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)}   } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)}   } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)}   }}} \, 7cos\theta d\theta\\

= \int\limits343 cos^{2}  \theta \, d\theta

8 0
3 years ago
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