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Ksivusya [100]
3 years ago
10

I need help in the problemsome people can help me plz

Mathematics
1 answer:
Leno4ka [110]3 years ago
5 0
2. Use the second equation (for y) to substitute into the first.
.. x +(2x +4) = 7
.. 3x +4 = 7 . . . . . collect terms
I know you can solve it from there. (x, y) = (1, 6)

3. Let "o" and "r" represent the numbers of orange fish and red fish, respectively.
.. o +r = 31 . . . . . there are 31 fish in a tank
.. o = 7 +r/2 . . . . there are 7 more orange fish than half the number of red fish

The second equation can be substituted into the first.
.. (7 +r/2) +r = 31
.. (3r/2) = 24 . . . . . . subtract 7
.. r = (2/3)*24 . . . . . .multiply by the inverse of the coefficient of r
I know you can solve it from there. (o, r) = (15, 16)
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A stock priced at $100 has a 70% probability of moving up and a 30% probability of moving down. If it moves up, it increases by
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The probability that after two period we will have the same value of $100 is:

p =0.21+0.21 = 0.42

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Stock moves up two times

For this case the final value would be:

$100 *1.02*1.02= $104.04

And the probability associated to this event is 0.7*0.7=0.49

Stock moves down two times

For this case the final value would be:

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And the probability associated to this event is 0.3*0.3=0.09

Stock moves up and then down

For this case the final value would be:

$100 *(1.02)*(1/1.02)= $100

And the probability associated to this event is 0.7*0.3=0.21

Stock moves down and then up

For this case the final value would be:

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