We know that
<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
It =11 not how is it 10 what did you think it was
Answer:
The answer is 9
Step-by-step explanation:
Binary Operations
The union of two sets A and B is denoted A ∪ B and
is defined as A ∪ B = {x|x ∈ A or x ∈ B}.
The intersection of two sets A and B is denoted A∩B
and is defined as A ∩ B = {x|x ∈ A and x ∈ B}.
Two sets are disjoint if they have no elements in common,
that is, A and B are disjoint if A ∩ B = ∅.
Yes it’s right the second group of terms should be -1(x+1)
