Say x is 1 1^2=1 4x=4 4*1=4 I believe that is what you were asking
Her statement is possible, the first rectangle could be equal to the second because x is unknown so if x was 5in in the first rectangle and - 1 in the second rectangle both problems would look like this 2 in & 5 in and the second one 5in & (2 in = (-1 +3)).
Answer:
A. $10.71
Step-by-step explanation:
I just met a friend for the first year old man who
