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SpyIntel [72]
3 years ago
13

How many meters is one centimeter cubed? Also, how many meters cubed are in one liter?

Mathematics
1 answer:
enot [183]3 years ago
7 0
1 m = 100 cm
1 m^3 = 1^6 cm^3


so 1 cm^3 = 10^-6 m^3

and 1 L = 1000 cm^3 = 10^-3 m^3
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The coordinates A(0,0) B(0,4) C(3,4) and D(3,0) are graphed and connected together. What 3 dimensional shape will be created whe
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All you have to do is rotate the current dots, and bam.

6 0
3 years ago
Which expression can be used to find m pls help
natali 33 [55]

Answer:

∠ U = 22.62°

Step-by-step explanation:

We can use the trigonometric expression to find ∠U by using the ratio:

sin(θ) = opposite/ hypotenuse

=> sin ∠U = 7.5/ 19.5

=> ∠ U = sin^{-1}( 7.5/ 19.5)

∴ ∠ U = 22.619° ≈ 22.62°

5 0
3 years ago
What is the solution to the system of linear equations graphed below? On a coordinate plane, 2 lines intersect at (negative 2.5,
Vitek1552 [10]

Answer:

D. (Negative 2 and one-half, negative 2)

Step-by-step explanation:

The intersection of the two lines is the solution to the system of linear equations. The two lines intersect at (-2.5, -2), then the solution to the system is x = -2.5 and y = -2

3 0
3 years ago
The coordinates of polygon ABCD are A(-4,-1), B(-2,3), C(2,2), and D(4,-3). Use these coordinates to complete the sentences belo
oee [108]

Answer:

The perimeter of polygon ABCD, to the nearest thousandth units is

22.227 units

The perimeter of polygon ABCD', to the nearest thousandth, would be 20.980 units

The area of polygon ABCD' is 19.5 units²

Step-by-step explanation:

The coordinates forming the polygon are

A (-4,-1), B(-2,3), C(2,2), and D(4,-3)

The perimeter then is given by the sum of the length of the sides as follows;

Length of line between two X and Y points distance, xi and yj apart is

length XY =  \sqrt{x^2+y^2}

Therefore, the length between points AB is

length AB = \sqrt{(-4 - (-2))^2+(-1-3)^2}

= \sqrt{(-4 +2)^2+(-4)^2} = \sqrt{-2^2+-4^2}  = \sqrt{20}  = 4.472 units

Similarly, length BC is given by

Length BC =  \sqrt{(-4)^2+1^2} =  \sqrt{17} = 4.123 units

Length CD = \sqrt{(-2)^2+5^2} =  \sqrt{29} = 5.385 units

Length DA = \sqrt{(8)^2+(-2)^2} =  \sqrt{68} = 8.246 units

The perimeter is equal to;

length AB + Length BC + Length CD + Length DA

= 4.472 + 4.123 + 5.385 + 8.246 = 22.227 units

If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

length AB + Length BC + Length CD + Length D'A

= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

 S_{\bigtriangleup} = (\frac{1}{2})|x_1y_2+x_2y_3+x_3y_1-x_1y_3-x_2y_1-x_3y_2|

= (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

Triangle ABC we have

A(-4,-1)

B(-2,3)

C(2,2)

S_{{\bigtriangleup}ABC} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(3-2)+(-2)(2-(-1)) +2((-1)-3)|

= =(\frac{1}{2})|-4-6 -8|= 9 units^2

Triangle ACD'

A(-4,-1)

C(2,2)

D'(3, -1)

S_{{\bigtriangleup}ACD'} = (\frac{1}{2})|x_1(y_2-y_3)+x_2(y_3-y_1) +x_3(y_1-y_2)|

=(\frac{1}{2})|(-4)(2+1)+(2)(-1+1) +3((-1)-2)| = \frac{21}{2} = 10.5 units²

Area of polygon =   S_{{\bigtriangleup}ABCD'} = S_{{\bigtriangleup}ABC} + S_{{\bigtriangleup}ACD'} = (9 + 10.5) units²

Area of polygon ABCD' = 19.5 units².

7 0
3 years ago
Cheyenne collects movies. She has 435 movies that are either comedy, scary, or sci-fi. She has the same number of videos for eac
tensa zangetsu [6.8K]
145 movies of each genre.

435/3= 145
4 0
3 years ago
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