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avanturin [10]
3 years ago
8

Find the solutions of the form x=a,y=0and x=0 ,y=b for the following equations: 2x+5y=10 and 2x+3y=6. is there any common soluti

on?
Mathematics
1 answer:
Arlecino [84]3 years ago
8 0

Answer:

 x=0 and y=2

Step-by-step explanation:

We have been given system of equations:

2x+5y=10     (1)

And 2x+3y=6     (2)

Subtract equation (2) from(1) we get:

2y=4

y=2

Now, substitute y=2 in equation(2) we get:

2x+3(2)=6

2x+6=6

2x=0

x=0

Hence, x=0 and y=2


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Find the distance between the complex numbers. z1 = 9 - 9i z2 = 10 - 9i
steposvetlana [31]

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The distance between the two given complex numbers = 9

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i):</em></u>-

Given  Z₁ = 9 - 9 i    and Z₂ = 10 -9 i

Let A and B represent complex numbers Z₁ and Z₂ respectively on the argand plane

⇒ A =  Z₁ = x₁ +i y₁ = 9 - 9 i and

    B = Z₂ = x₂+ i y₂ = 10 -9 i

Let (x₁ , y₁) = ( 9, -9)

     (x₂, y₂) = (10, -9)

<u>Step(ii)</u>:-

<em>The distance between the two points are </em>

    A B   =   \sqrt{(x_{2} - x_{1})^{2}+(y_{2} - y_{1})^{2}    }

    A B =   \sqrt{(10 - 1)^{2}+(-9 - (-9))^{2}    }

   AB   = \sqrt{(9)^{2} +(-9+9)^{2} }

 <em> AB    =  √81 = 9</em>

<u><em>Conclusion:-</em></u>

The distance between the two given complex numbers = 9

<u><em></em></u>

3 0
2 years ago
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