Question

determine the shape of the graph represented by this equation: -x^2 + 4y^2 - 6x -48y + 139= 0 Ellipse or hyperbole

Answer 1

ANSWER

Hyperbole.

EXPLANATION

The given equation is

$- {x}^{2} + 4 {y}^{2} - 6x - 48y + 139 = 0$

We use the sign of the quadratic terms to determine whether the conic is a hyperbole or an ellipse.

Since the sign of the coefficient of the quadratic terms are opposite, the conic is a hyperbole.

Answer 2

Answer:

The graph of the given function yields a hyperbola shown in the attached image below