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DanielleElmas [232]
3 years ago
8

How do I solve this equation? 4-y/5=2-2y/8

Mathematics
2 answers:
Aliun [14]3 years ago
8 0

y=−40

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

4−y5=2−2y8

4+−15y=2+−14y

−15y+4=−14y+2

Step 2: Add 1/4y to both sides.

−15y+4+14y=−14y+2+14y

120y+4=2

Step 3: Subtract 4 from both sides.

120y+4−4=2−4

120y=−2

Step 4: Multiply both sides by 20.

20*(120y)=(20)*(−2)

Answer:

y=−40

PtichkaEL [24]3 years ago
3 0

Answer:

y= -40

Step-by-step explanation:

4 - y/5 = 2 - 2y/8

4 - y/5 = 2 - y/4

4 x 20 - y x 20/5 = 2 x 20 - y x 20/4 (reduce the fractions)

4 x 20 - 4y = 2 x 20 - 5y

80 - 4y = 2 x 20 - 5y

80 - 4y = 40 - 5y

-4y + 5y = 40 - 80

y = 40 - 80

y = - 40

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Answer:

The ratio in which the line x-y-2=0 divides the line joining A(3,-1) and B(8,9) is in the ratio 2:3

Step-by-step explanation:

Let (x, y) be the coordinates of point of intersection.

Hence x=(a*8+1*3)(a+1) = (8a+3)/(a+1)

and

y = {a*9+1*(-1)}/(a+1)=(9a-1)/(a+1)

Since this point lies on the line x-y-2=0

Hence (8a+3)/(a+1)-(9a-1)/(a+1)-2=0

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i.e. 2:3

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