If <em>a</em> is fixed and <em>b</em>,<em>c</em> are unknowns then the equation <em>b</em>+<em>c</em>=10-<em>a</em> has 11-<em>a</em> solutions. They are pairs (b,c): (0,10-a), (1,9-a), (2,8-a), ... (10-a,0). As <em>a</em> runs from 0 to 10 we have total number of solutions (11-0)+(11-1)+...(11-1)=11+10+...+1=(1+11)*11/2=66.
Answer:
if we estimate this number its going to be 700,000
Answer:
inverse operations (KristaKingMath)
Answer:
x + 79 = 90
x = 11 degrees
Step-by-step explanation:
NQ
This is because you have to see what R is congruent to (based off the order) and you see N. Then you do the same thing for T and you get Q.