All categories

3 years ago

Perform the indicated operation. 10 3/7 + 19 5/9

2 answers:

4 0

Given expression is

$10 \frac{3}{7} + 19 \frac{5}{9}$

Now convert mixed fraction as improper fraction as

$10 \frac{3}{7} + 19 \frac{5}{9} = \frac{10*7 + 3}{7} + \frac{19*9+5}{9}$
                                                         $= \frac{73}{7} + \frac{176}{9}$
                                                          $= \frac{73*9 + 176 * 7}{63}$
                                                         $= \frac{657 + 1232}{63} = \frac{1889}{63}$
Now we can convert $\frac{1889}{63 } = 29 \frac{62}{63}$

So the answer is $29 \frac{62}63}$

ratelena [41]3 years ago

3 0

Answer:

29 62/63

Step-by-step explanation:

You might be interested in

Number seven on the page

prohojiy [21]

Multiply 9.75 by 1.5 to get 14.63 fluid ounces.

6 0

3 years ago

A square is drawn below what is the value of x

Andru [333]

Answer:

You donf have the picture shown, how is anybody supposed to work on it

3 0

2 years ago

Read 2 more answers

2+cotA=1 homework help

Alex Ar [27]

$2+\cot A=1\implies \cot A=-1\implies \tan A=-1$

This happens whenever $A=\dfrac{3\pi}4$ or $A=\dfrac{7\pi}4$ . More generally, $\tan A=-1$ whenever you start with one of these angles and add any multiple of $\pi$ , so the general solution would be $A=\dfrac{3\pi}4+n\pi$ , where $n$ is any integer. (Notice that when $n=1$ , you end up with $\dfrac{7\pi}4$ .)

3 0

3 years ago

Weights were recorded for all nurses at a particular hospital, the mean weight for an individual nurse was 135 lbs. with a stand

Aloiza [94]

Given:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19

Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.

Estimate of sample mean
$\bar{x}=\mu=135$

Estimate of sample standard deviation
$\s=\sqrt{\frac{\sigma^2}{n}}$
$=\sqrt{\frac{15^2}{19}}=3.44124$ to 5 decimal places.

Thus, using the normal probability table,
$P(125$
$=P(\frac{125-135}{3.44124}$
$=P(-2.90593$
$=P(Z$
$=P(Z$

Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=0.0712858

3 0

2 years ago

What is 45 ÷ 2 over 3

Veronika [31]

the answer is 7.5 :)))

7 0

2 years ago

Read 2 more answers