<img src="https://tex.z-dn.net/?f=%5Cfrac%7B2x%2B4%7D%7Bx%5E%7B2%7D-2x-8%20%7D" id="TexFormula1" title="\frac{2x+4}{x^{2}-2x-8 }

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White raven [17]

2 years ago

" alt="\frac{2x+4}{x^{2}-2x-8 }" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

lisabon 2012 [21]2 years ago

6 0

Answer:

$\frac{2}{x-4}$

Step-by-step explanation:

$\frac{2x+4}{x^2-2x-8}$

Factor both the numerator and denominator

$\frac{2(x+2)}{(x-4)(x+2)}$

The $x+2$ 's cancel out

The equation in its simplest form is $\frac{2}{x-4}$

Hope this helps!

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Finding the first term :

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I hope this helps . Let me know if you need further clarification .

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