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White raven [17]
3 years ago
13

" alt="\frac{2x+4}{x^{2}-2x-8 }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
lisabon 2012 [21]3 years ago
6 0

Answer:

\frac{2}{x-4}

Step-by-step explanation:

\frac{2x+4}{x^2-2x-8}

Factor both the numerator and denominator

\frac{2(x+2)}{(x-4)(x+2)}

The x+2 's cancel out

The equation in its simplest form is \frac{2}{x-4}

Hope this helps!

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Step-by-step explanation:

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terms: n, 5n

like terms: n, 5n

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coefficient: 6

constant: 0

=======================

12c - c = 12c - c + 0

terms: 12c, -c

like terms: 12c, -c

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constant: 0

========================

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like terms: -4j, -4j and -1, 6

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7 0
4 years ago
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