Question

" alt="\frac{2x+4}{x^{2}-2x-8 }" align="absmiddle" class="latex-formula">

Answer 1

Answer:

$\frac{2}{x-4}$

Step-by-step explanation:

$\frac{2x+4}{x^2-2x-8}$

Factor both the numerator and denominator

$\frac{2(x+2)}{(x-4)(x+2)}$

The $x+2$ 's cancel out

The equation in its simplest form is $\frac{2}{x-4}$

Hope this helps!